Proof of Theorem lgamgulmlem1
Step | Hyp | Ref
| Expression |
1 | | lgamgulm.u |
. 2
⊢ 𝑈 = {𝑥 ∈ ℂ ∣ ((abs‘𝑥) ≤ 𝑅 ∧ ∀𝑘 ∈ ℕ0 (1 / 𝑅) ≤ (abs‘(𝑥 + 𝑘)))} |
2 | | simp2 1055 |
. . . 4
⊢ ((𝜑 ∧ 𝑥 ∈ ℂ ∧ ((abs‘𝑥) ≤ 𝑅 ∧ ∀𝑘 ∈ ℕ0 (1 / 𝑅) ≤ (abs‘(𝑥 + 𝑘)))) → 𝑥 ∈ ℂ) |
3 | | lgamgulm.r |
. . . . . . . . 9
⊢ (𝜑 → 𝑅 ∈ ℕ) |
4 | 3 | 3ad2ant1 1075 |
. . . . . . . 8
⊢ ((𝜑 ∧ 𝑥 ∈ ℂ ∧ ((abs‘𝑥) ≤ 𝑅 ∧ ∀𝑘 ∈ ℕ0 (1 / 𝑅) ≤ (abs‘(𝑥 + 𝑘)))) → 𝑅 ∈ ℕ) |
5 | 4 | nnred 10912 |
. . . . . . 7
⊢ ((𝜑 ∧ 𝑥 ∈ ℂ ∧ ((abs‘𝑥) ≤ 𝑅 ∧ ∀𝑘 ∈ ℕ0 (1 / 𝑅) ≤ (abs‘(𝑥 + 𝑘)))) → 𝑅 ∈ ℝ) |
6 | 4 | nngt0d 10941 |
. . . . . . 7
⊢ ((𝜑 ∧ 𝑥 ∈ ℂ ∧ ((abs‘𝑥) ≤ 𝑅 ∧ ∀𝑘 ∈ ℕ0 (1 / 𝑅) ≤ (abs‘(𝑥 + 𝑘)))) → 0 < 𝑅) |
7 | 5, 6 | recgt0d 10837 |
. . . . . 6
⊢ ((𝜑 ∧ 𝑥 ∈ ℂ ∧ ((abs‘𝑥) ≤ 𝑅 ∧ ∀𝑘 ∈ ℕ0 (1 / 𝑅) ≤ (abs‘(𝑥 + 𝑘)))) → 0 < (1 / 𝑅)) |
8 | | 0red 9920 |
. . . . . . 7
⊢ ((𝜑 ∧ 𝑥 ∈ ℂ ∧ ((abs‘𝑥) ≤ 𝑅 ∧ ∀𝑘 ∈ ℕ0 (1 / 𝑅) ≤ (abs‘(𝑥 + 𝑘)))) → 0 ∈
ℝ) |
9 | 4 | nnrecred 10943 |
. . . . . . 7
⊢ ((𝜑 ∧ 𝑥 ∈ ℂ ∧ ((abs‘𝑥) ≤ 𝑅 ∧ ∀𝑘 ∈ ℕ0 (1 / 𝑅) ≤ (abs‘(𝑥 + 𝑘)))) → (1 / 𝑅) ∈ ℝ) |
10 | 8, 9 | ltnled 10063 |
. . . . . 6
⊢ ((𝜑 ∧ 𝑥 ∈ ℂ ∧ ((abs‘𝑥) ≤ 𝑅 ∧ ∀𝑘 ∈ ℕ0 (1 / 𝑅) ≤ (abs‘(𝑥 + 𝑘)))) → (0 < (1 / 𝑅) ↔ ¬ (1 / 𝑅) ≤ 0)) |
11 | 7, 10 | mpbid 221 |
. . . . 5
⊢ ((𝜑 ∧ 𝑥 ∈ ℂ ∧ ((abs‘𝑥) ≤ 𝑅 ∧ ∀𝑘 ∈ ℕ0 (1 / 𝑅) ≤ (abs‘(𝑥 + 𝑘)))) → ¬ (1 / 𝑅) ≤ 0) |
12 | | oveq2 6557 |
. . . . . . . . . . 11
⊢ (𝑘 = -𝑥 → (𝑥 + 𝑘) = (𝑥 + -𝑥)) |
13 | 12 | fveq2d 6107 |
. . . . . . . . . 10
⊢ (𝑘 = -𝑥 → (abs‘(𝑥 + 𝑘)) = (abs‘(𝑥 + -𝑥))) |
14 | 13 | breq2d 4595 |
. . . . . . . . 9
⊢ (𝑘 = -𝑥 → ((1 / 𝑅) ≤ (abs‘(𝑥 + 𝑘)) ↔ (1 / 𝑅) ≤ (abs‘(𝑥 + -𝑥)))) |
15 | 14 | rspccv 3279 |
. . . . . . . 8
⊢
(∀𝑘 ∈
ℕ0 (1 / 𝑅)
≤ (abs‘(𝑥 + 𝑘)) → (-𝑥 ∈ ℕ0 → (1 / 𝑅) ≤ (abs‘(𝑥 + -𝑥)))) |
16 | 15 | adantl 481 |
. . . . . . 7
⊢
(((abs‘𝑥) ≤
𝑅 ∧ ∀𝑘 ∈ ℕ0 (1 /
𝑅) ≤ (abs‘(𝑥 + 𝑘))) → (-𝑥 ∈ ℕ0 → (1 / 𝑅) ≤ (abs‘(𝑥 + -𝑥)))) |
17 | 16 | 3ad2ant3 1077 |
. . . . . 6
⊢ ((𝜑 ∧ 𝑥 ∈ ℂ ∧ ((abs‘𝑥) ≤ 𝑅 ∧ ∀𝑘 ∈ ℕ0 (1 / 𝑅) ≤ (abs‘(𝑥 + 𝑘)))) → (-𝑥 ∈ ℕ0 → (1 / 𝑅) ≤ (abs‘(𝑥 + -𝑥)))) |
18 | 2 | negidd 10261 |
. . . . . . . . 9
⊢ ((𝜑 ∧ 𝑥 ∈ ℂ ∧ ((abs‘𝑥) ≤ 𝑅 ∧ ∀𝑘 ∈ ℕ0 (1 / 𝑅) ≤ (abs‘(𝑥 + 𝑘)))) → (𝑥 + -𝑥) = 0) |
19 | 18 | fveq2d 6107 |
. . . . . . . 8
⊢ ((𝜑 ∧ 𝑥 ∈ ℂ ∧ ((abs‘𝑥) ≤ 𝑅 ∧ ∀𝑘 ∈ ℕ0 (1 / 𝑅) ≤ (abs‘(𝑥 + 𝑘)))) → (abs‘(𝑥 + -𝑥)) = (abs‘0)) |
20 | | abs0 13873 |
. . . . . . . 8
⊢
(abs‘0) = 0 |
21 | 19, 20 | syl6eq 2660 |
. . . . . . 7
⊢ ((𝜑 ∧ 𝑥 ∈ ℂ ∧ ((abs‘𝑥) ≤ 𝑅 ∧ ∀𝑘 ∈ ℕ0 (1 / 𝑅) ≤ (abs‘(𝑥 + 𝑘)))) → (abs‘(𝑥 + -𝑥)) = 0) |
22 | 21 | breq2d 4595 |
. . . . . 6
⊢ ((𝜑 ∧ 𝑥 ∈ ℂ ∧ ((abs‘𝑥) ≤ 𝑅 ∧ ∀𝑘 ∈ ℕ0 (1 / 𝑅) ≤ (abs‘(𝑥 + 𝑘)))) → ((1 / 𝑅) ≤ (abs‘(𝑥 + -𝑥)) ↔ (1 / 𝑅) ≤ 0)) |
23 | 17, 22 | sylibd 228 |
. . . . 5
⊢ ((𝜑 ∧ 𝑥 ∈ ℂ ∧ ((abs‘𝑥) ≤ 𝑅 ∧ ∀𝑘 ∈ ℕ0 (1 / 𝑅) ≤ (abs‘(𝑥 + 𝑘)))) → (-𝑥 ∈ ℕ0 → (1 / 𝑅) ≤ 0)) |
24 | 11, 23 | mtod 188 |
. . . 4
⊢ ((𝜑 ∧ 𝑥 ∈ ℂ ∧ ((abs‘𝑥) ≤ 𝑅 ∧ ∀𝑘 ∈ ℕ0 (1 / 𝑅) ≤ (abs‘(𝑥 + 𝑘)))) → ¬ -𝑥 ∈ ℕ0) |
25 | | eldmgm 24548 |
. . . 4
⊢ (𝑥 ∈ (ℂ ∖
(ℤ ∖ ℕ)) ↔ (𝑥 ∈ ℂ ∧ ¬ -𝑥 ∈
ℕ0)) |
26 | 2, 24, 25 | sylanbrc 695 |
. . 3
⊢ ((𝜑 ∧ 𝑥 ∈ ℂ ∧ ((abs‘𝑥) ≤ 𝑅 ∧ ∀𝑘 ∈ ℕ0 (1 / 𝑅) ≤ (abs‘(𝑥 + 𝑘)))) → 𝑥 ∈ (ℂ ∖ (ℤ ∖
ℕ))) |
27 | 26 | rabssdv 3645 |
. 2
⊢ (𝜑 → {𝑥 ∈ ℂ ∣ ((abs‘𝑥) ≤ 𝑅 ∧ ∀𝑘 ∈ ℕ0 (1 / 𝑅) ≤ (abs‘(𝑥 + 𝑘)))} ⊆ (ℂ ∖ (ℤ
∖ ℕ))) |
28 | 1, 27 | syl5eqss 3612 |
1
⊢ (𝜑 → 𝑈 ⊆ (ℂ ∖ (ℤ ∖
ℕ))) |