Step | Hyp | Ref
| Expression |
1 | | is2spthonot 26391 |
. . . 4
⊢ ((𝑉 ∈ 𝑋 ∧ 𝐸 ∈ 𝑌) → (𝑉 2SPathOnOt 𝐸) = (𝑎 ∈ 𝑉, 𝑏 ∈ 𝑉 ↦ {𝑡 ∈ ((𝑉 × 𝑉) × 𝑉) ∣ ∃𝑓∃𝑝(𝑓(𝑎(𝑉 SPathOn 𝐸)𝑏)𝑝 ∧ (#‘𝑓) = 2 ∧ ((1st
‘(1st ‘𝑡)) = 𝑎 ∧ (2nd ‘(1st
‘𝑡)) = (𝑝‘1) ∧ (2nd
‘𝑡) = 𝑏))})) |
2 | 1 | adantr 480 |
. . 3
⊢ (((𝑉 ∈ 𝑋 ∧ 𝐸 ∈ 𝑌) ∧ (𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑉)) → (𝑉 2SPathOnOt 𝐸) = (𝑎 ∈ 𝑉, 𝑏 ∈ 𝑉 ↦ {𝑡 ∈ ((𝑉 × 𝑉) × 𝑉) ∣ ∃𝑓∃𝑝(𝑓(𝑎(𝑉 SPathOn 𝐸)𝑏)𝑝 ∧ (#‘𝑓) = 2 ∧ ((1st
‘(1st ‘𝑡)) = 𝑎 ∧ (2nd ‘(1st
‘𝑡)) = (𝑝‘1) ∧ (2nd
‘𝑡) = 𝑏))})) |
3 | 2 | oveqd 6566 |
. 2
⊢ (((𝑉 ∈ 𝑋 ∧ 𝐸 ∈ 𝑌) ∧ (𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑉)) → (𝐴(𝑉 2SPathOnOt 𝐸)𝐵) = (𝐴(𝑎 ∈ 𝑉, 𝑏 ∈ 𝑉 ↦ {𝑡 ∈ ((𝑉 × 𝑉) × 𝑉) ∣ ∃𝑓∃𝑝(𝑓(𝑎(𝑉 SPathOn 𝐸)𝑏)𝑝 ∧ (#‘𝑓) = 2 ∧ ((1st
‘(1st ‘𝑡)) = 𝑎 ∧ (2nd ‘(1st
‘𝑡)) = (𝑝‘1) ∧ (2nd
‘𝑡) = 𝑏))})𝐵)) |
4 | | simprl 790 |
. . 3
⊢ (((𝑉 ∈ 𝑋 ∧ 𝐸 ∈ 𝑌) ∧ (𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑉)) → 𝐴 ∈ 𝑉) |
5 | | simprr 792 |
. . 3
⊢ (((𝑉 ∈ 𝑋 ∧ 𝐸 ∈ 𝑌) ∧ (𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑉)) → 𝐵 ∈ 𝑉) |
6 | | 3xpexg 6859 |
. . . . 5
⊢ (𝑉 ∈ 𝑋 → ((𝑉 × 𝑉) × 𝑉) ∈ V) |
7 | 6 | ad2antrr 758 |
. . . 4
⊢ (((𝑉 ∈ 𝑋 ∧ 𝐸 ∈ 𝑌) ∧ (𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑉)) → ((𝑉 × 𝑉) × 𝑉) ∈ V) |
8 | | rabexg 4739 |
. . . 4
⊢ (((𝑉 × 𝑉) × 𝑉) ∈ V → {𝑡 ∈ ((𝑉 × 𝑉) × 𝑉) ∣ ∃𝑓∃𝑝(𝑓(𝐴(𝑉 SPathOn 𝐸)𝐵)𝑝 ∧ (#‘𝑓) = 2 ∧ ((1st
‘(1st ‘𝑡)) = 𝐴 ∧ (2nd
‘(1st ‘𝑡)) = (𝑝‘1) ∧ (2nd ‘𝑡) = 𝐵))} ∈ V) |
9 | 7, 8 | syl 17 |
. . 3
⊢ (((𝑉 ∈ 𝑋 ∧ 𝐸 ∈ 𝑌) ∧ (𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑉)) → {𝑡 ∈ ((𝑉 × 𝑉) × 𝑉) ∣ ∃𝑓∃𝑝(𝑓(𝐴(𝑉 SPathOn 𝐸)𝐵)𝑝 ∧ (#‘𝑓) = 2 ∧ ((1st
‘(1st ‘𝑡)) = 𝐴 ∧ (2nd
‘(1st ‘𝑡)) = (𝑝‘1) ∧ (2nd ‘𝑡) = 𝐵))} ∈ V) |
10 | | oveq12 6558 |
. . . . . . . 8
⊢ ((𝑎 = 𝐴 ∧ 𝑏 = 𝐵) → (𝑎(𝑉 SPathOn 𝐸)𝑏) = (𝐴(𝑉 SPathOn 𝐸)𝐵)) |
11 | 10 | breqd 4594 |
. . . . . . 7
⊢ ((𝑎 = 𝐴 ∧ 𝑏 = 𝐵) → (𝑓(𝑎(𝑉 SPathOn 𝐸)𝑏)𝑝 ↔ 𝑓(𝐴(𝑉 SPathOn 𝐸)𝐵)𝑝)) |
12 | | eqeq2 2621 |
. . . . . . . . 9
⊢ (𝑎 = 𝐴 → ((1st
‘(1st ‘𝑡)) = 𝑎 ↔ (1st
‘(1st ‘𝑡)) = 𝐴)) |
13 | 12 | adantr 480 |
. . . . . . . 8
⊢ ((𝑎 = 𝐴 ∧ 𝑏 = 𝐵) → ((1st
‘(1st ‘𝑡)) = 𝑎 ↔ (1st
‘(1st ‘𝑡)) = 𝐴)) |
14 | | eqeq2 2621 |
. . . . . . . . 9
⊢ (𝑏 = 𝐵 → ((2nd ‘𝑡) = 𝑏 ↔ (2nd ‘𝑡) = 𝐵)) |
15 | 14 | adantl 481 |
. . . . . . . 8
⊢ ((𝑎 = 𝐴 ∧ 𝑏 = 𝐵) → ((2nd ‘𝑡) = 𝑏 ↔ (2nd ‘𝑡) = 𝐵)) |
16 | 13, 15 | 3anbi13d 1393 |
. . . . . . 7
⊢ ((𝑎 = 𝐴 ∧ 𝑏 = 𝐵) → (((1st
‘(1st ‘𝑡)) = 𝑎 ∧ (2nd ‘(1st
‘𝑡)) = (𝑝‘1) ∧ (2nd
‘𝑡) = 𝑏) ↔ ((1st
‘(1st ‘𝑡)) = 𝐴 ∧ (2nd
‘(1st ‘𝑡)) = (𝑝‘1) ∧ (2nd ‘𝑡) = 𝐵))) |
17 | 11, 16 | 3anbi13d 1393 |
. . . . . 6
⊢ ((𝑎 = 𝐴 ∧ 𝑏 = 𝐵) → ((𝑓(𝑎(𝑉 SPathOn 𝐸)𝑏)𝑝 ∧ (#‘𝑓) = 2 ∧ ((1st
‘(1st ‘𝑡)) = 𝑎 ∧ (2nd ‘(1st
‘𝑡)) = (𝑝‘1) ∧ (2nd
‘𝑡) = 𝑏)) ↔ (𝑓(𝐴(𝑉 SPathOn 𝐸)𝐵)𝑝 ∧ (#‘𝑓) = 2 ∧ ((1st
‘(1st ‘𝑡)) = 𝐴 ∧ (2nd
‘(1st ‘𝑡)) = (𝑝‘1) ∧ (2nd ‘𝑡) = 𝐵)))) |
18 | 17 | 2exbidv 1839 |
. . . . 5
⊢ ((𝑎 = 𝐴 ∧ 𝑏 = 𝐵) → (∃𝑓∃𝑝(𝑓(𝑎(𝑉 SPathOn 𝐸)𝑏)𝑝 ∧ (#‘𝑓) = 2 ∧ ((1st
‘(1st ‘𝑡)) = 𝑎 ∧ (2nd ‘(1st
‘𝑡)) = (𝑝‘1) ∧ (2nd
‘𝑡) = 𝑏)) ↔ ∃𝑓∃𝑝(𝑓(𝐴(𝑉 SPathOn 𝐸)𝐵)𝑝 ∧ (#‘𝑓) = 2 ∧ ((1st
‘(1st ‘𝑡)) = 𝐴 ∧ (2nd
‘(1st ‘𝑡)) = (𝑝‘1) ∧ (2nd ‘𝑡) = 𝐵)))) |
19 | 18 | rabbidv 3164 |
. . . 4
⊢ ((𝑎 = 𝐴 ∧ 𝑏 = 𝐵) → {𝑡 ∈ ((𝑉 × 𝑉) × 𝑉) ∣ ∃𝑓∃𝑝(𝑓(𝑎(𝑉 SPathOn 𝐸)𝑏)𝑝 ∧ (#‘𝑓) = 2 ∧ ((1st
‘(1st ‘𝑡)) = 𝑎 ∧ (2nd ‘(1st
‘𝑡)) = (𝑝‘1) ∧ (2nd
‘𝑡) = 𝑏))} = {𝑡 ∈ ((𝑉 × 𝑉) × 𝑉) ∣ ∃𝑓∃𝑝(𝑓(𝐴(𝑉 SPathOn 𝐸)𝐵)𝑝 ∧ (#‘𝑓) = 2 ∧ ((1st
‘(1st ‘𝑡)) = 𝐴 ∧ (2nd
‘(1st ‘𝑡)) = (𝑝‘1) ∧ (2nd ‘𝑡) = 𝐵))}) |
20 | | eqid 2610 |
. . . 4
⊢ (𝑎 ∈ 𝑉, 𝑏 ∈ 𝑉 ↦ {𝑡 ∈ ((𝑉 × 𝑉) × 𝑉) ∣ ∃𝑓∃𝑝(𝑓(𝑎(𝑉 SPathOn 𝐸)𝑏)𝑝 ∧ (#‘𝑓) = 2 ∧ ((1st
‘(1st ‘𝑡)) = 𝑎 ∧ (2nd ‘(1st
‘𝑡)) = (𝑝‘1) ∧ (2nd
‘𝑡) = 𝑏))}) = (𝑎 ∈ 𝑉, 𝑏 ∈ 𝑉 ↦ {𝑡 ∈ ((𝑉 × 𝑉) × 𝑉) ∣ ∃𝑓∃𝑝(𝑓(𝑎(𝑉 SPathOn 𝐸)𝑏)𝑝 ∧ (#‘𝑓) = 2 ∧ ((1st
‘(1st ‘𝑡)) = 𝑎 ∧ (2nd ‘(1st
‘𝑡)) = (𝑝‘1) ∧ (2nd
‘𝑡) = 𝑏))}) |
21 | 19, 20 | ovmpt2ga 6688 |
. . 3
⊢ ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑉 ∧ {𝑡 ∈ ((𝑉 × 𝑉) × 𝑉) ∣ ∃𝑓∃𝑝(𝑓(𝐴(𝑉 SPathOn 𝐸)𝐵)𝑝 ∧ (#‘𝑓) = 2 ∧ ((1st
‘(1st ‘𝑡)) = 𝐴 ∧ (2nd
‘(1st ‘𝑡)) = (𝑝‘1) ∧ (2nd ‘𝑡) = 𝐵))} ∈ V) → (𝐴(𝑎 ∈ 𝑉, 𝑏 ∈ 𝑉 ↦ {𝑡 ∈ ((𝑉 × 𝑉) × 𝑉) ∣ ∃𝑓∃𝑝(𝑓(𝑎(𝑉 SPathOn 𝐸)𝑏)𝑝 ∧ (#‘𝑓) = 2 ∧ ((1st
‘(1st ‘𝑡)) = 𝑎 ∧ (2nd ‘(1st
‘𝑡)) = (𝑝‘1) ∧ (2nd
‘𝑡) = 𝑏))})𝐵) = {𝑡 ∈ ((𝑉 × 𝑉) × 𝑉) ∣ ∃𝑓∃𝑝(𝑓(𝐴(𝑉 SPathOn 𝐸)𝐵)𝑝 ∧ (#‘𝑓) = 2 ∧ ((1st
‘(1st ‘𝑡)) = 𝐴 ∧ (2nd
‘(1st ‘𝑡)) = (𝑝‘1) ∧ (2nd ‘𝑡) = 𝐵))}) |
22 | 4, 5, 9, 21 | syl3anc 1318 |
. 2
⊢ (((𝑉 ∈ 𝑋 ∧ 𝐸 ∈ 𝑌) ∧ (𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑉)) → (𝐴(𝑎 ∈ 𝑉, 𝑏 ∈ 𝑉 ↦ {𝑡 ∈ ((𝑉 × 𝑉) × 𝑉) ∣ ∃𝑓∃𝑝(𝑓(𝑎(𝑉 SPathOn 𝐸)𝑏)𝑝 ∧ (#‘𝑓) = 2 ∧ ((1st
‘(1st ‘𝑡)) = 𝑎 ∧ (2nd ‘(1st
‘𝑡)) = (𝑝‘1) ∧ (2nd
‘𝑡) = 𝑏))})𝐵) = {𝑡 ∈ ((𝑉 × 𝑉) × 𝑉) ∣ ∃𝑓∃𝑝(𝑓(𝐴(𝑉 SPathOn 𝐸)𝐵)𝑝 ∧ (#‘𝑓) = 2 ∧ ((1st
‘(1st ‘𝑡)) = 𝐴 ∧ (2nd
‘(1st ‘𝑡)) = (𝑝‘1) ∧ (2nd ‘𝑡) = 𝐵))}) |
23 | 3, 22 | eqtrd 2644 |
1
⊢ (((𝑉 ∈ 𝑋 ∧ 𝐸 ∈ 𝑌) ∧ (𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑉)) → (𝐴(𝑉 2SPathOnOt 𝐸)𝐵) = {𝑡 ∈ ((𝑉 × 𝑉) × 𝑉) ∣ ∃𝑓∃𝑝(𝑓(𝐴(𝑉 SPathOn 𝐸)𝐵)𝑝 ∧ (#‘𝑓) = 2 ∧ ((1st
‘(1st ‘𝑡)) = 𝐴 ∧ (2nd
‘(1st ‘𝑡)) = (𝑝‘1) ∧ (2nd ‘𝑡) = 𝐵))}) |