Theorem fvcofneq 6275

Description: The values of two function compositions are equal if the values of the composed functions are pairwise equal. (Contributed by AV, 26-Jan-2019.)

Assertion

Ref	Expression
fvcofneq	⊢ ((𝐺 Fn 𝐴 ∧ 𝐾 Fn 𝐵) → ((𝑋 ∈ (𝐴 ∩ 𝐵) ∧ (𝐺‘𝑋) = (𝐾‘𝑋) ∧ ∀𝑥 ∈ (ran 𝐺 ∩ ran 𝐾)(𝐹‘𝑥) = (𝐻‘𝑥)) → ((𝐹 ∘ 𝐺)‘𝑋) = ((𝐻 ∘ 𝐾)‘𝑋)))

Distinct variable groups:   𝑥,𝐹   𝑥,𝐺   𝑥,𝐻   𝑥,𝐾   𝑥,𝑋

Allowed substitution hints:   𝐴(𝑥)   𝐵(𝑥)

Proof of Theorem fvcofneq

Step	Hyp	Ref	Expression
1		simpl 472	. . . 4 ⊢ ((𝐺 Fn 𝐴 ∧ 𝐾 Fn 𝐵) → 𝐺 Fn 𝐴)
2		elin 3758	. . . . . 6 ⊢ (𝑋 ∈ (𝐴 ∩ 𝐵) ↔ (𝑋 ∈ 𝐴 ∧ 𝑋 ∈ 𝐵))
3		simpl 472	. . . . . 6 ⊢ ((𝑋 ∈ 𝐴 ∧ 𝑋 ∈ 𝐵) → 𝑋 ∈ 𝐴)
4	2, 3	sylbi 206	. . . . 5 ⊢ (𝑋 ∈ (𝐴 ∩ 𝐵) → 𝑋 ∈ 𝐴)
5	4	3ad2ant1 1075	. . . 4 ⊢ ((𝑋 ∈ (𝐴 ∩ 𝐵) ∧ (𝐺‘𝑋) = (𝐾‘𝑋) ∧ ∀𝑥 ∈ (ran 𝐺 ∩ ran 𝐾)(𝐹‘𝑥) = (𝐻‘𝑥)) → 𝑋 ∈ 𝐴)
6		fvco2 6183	. . . 4 ⊢ ((𝐺 Fn 𝐴 ∧ 𝑋 ∈ 𝐴) → ((𝐹 ∘ 𝐺)‘𝑋) = (𝐹‘(𝐺‘𝑋)))
7	1, 5, 6	syl2an 493	. . 3 ⊢ (((𝐺 Fn 𝐴 ∧ 𝐾 Fn 𝐵) ∧ (𝑋 ∈ (𝐴 ∩ 𝐵) ∧ (𝐺‘𝑋) = (𝐾‘𝑋) ∧ ∀𝑥 ∈ (ran 𝐺 ∩ ran 𝐾)(𝐹‘𝑥) = (𝐻‘𝑥))) → ((𝐹 ∘ 𝐺)‘𝑋) = (𝐹‘(𝐺‘𝑋)))
8		simpr 476	. . . . 5 ⊢ ((𝐺 Fn 𝐴 ∧ 𝐾 Fn 𝐵) → 𝐾 Fn 𝐵)
9		simpr 476	. . . . . . 7 ⊢ ((𝑋 ∈ 𝐴 ∧ 𝑋 ∈ 𝐵) → 𝑋 ∈ 𝐵)
10	2, 9	sylbi 206	. . . . . 6 ⊢ (𝑋 ∈ (𝐴 ∩ 𝐵) → 𝑋 ∈ 𝐵)
11	10	3ad2ant1 1075	. . . . 5 ⊢ ((𝑋 ∈ (𝐴 ∩ 𝐵) ∧ (𝐺‘𝑋) = (𝐾‘𝑋) ∧ ∀𝑥 ∈ (ran 𝐺 ∩ ran 𝐾)(𝐹‘𝑥) = (𝐻‘𝑥)) → 𝑋 ∈ 𝐵)
12		fvco2 6183	. . . . 5 ⊢ ((𝐾 Fn 𝐵 ∧ 𝑋 ∈ 𝐵) → ((𝐻 ∘ 𝐾)‘𝑋) = (𝐻‘(𝐾‘𝑋)))
13	8, 11, 12	syl2an 493	. . . 4 ⊢ (((𝐺 Fn 𝐴 ∧ 𝐾 Fn 𝐵) ∧ (𝑋 ∈ (𝐴 ∩ 𝐵) ∧ (𝐺‘𝑋) = (𝐾‘𝑋) ∧ ∀𝑥 ∈ (ran 𝐺 ∩ ran 𝐾)(𝐹‘𝑥) = (𝐻‘𝑥))) → ((𝐻 ∘ 𝐾)‘𝑋) = (𝐻‘(𝐾‘𝑋)))
14		fveq2 6103	. . . . . . 7 ⊢ ((𝐾‘𝑋) = (𝐺‘𝑋) → (𝐻‘(𝐾‘𝑋)) = (𝐻‘(𝐺‘𝑋)))
15	14	eqcoms 2618	. . . . . 6 ⊢ ((𝐺‘𝑋) = (𝐾‘𝑋) → (𝐻‘(𝐾‘𝑋)) = (𝐻‘(𝐺‘𝑋)))
16	15	3ad2ant2 1076	. . . . 5 ⊢ ((𝑋 ∈ (𝐴 ∩ 𝐵) ∧ (𝐺‘𝑋) = (𝐾‘𝑋) ∧ ∀𝑥 ∈ (ran 𝐺 ∩ ran 𝐾)(𝐹‘𝑥) = (𝐻‘𝑥)) → (𝐻‘(𝐾‘𝑋)) = (𝐻‘(𝐺‘𝑋)))
17	16	adantl 481	. . . 4 ⊢ (((𝐺 Fn 𝐴 ∧ 𝐾 Fn 𝐵) ∧ (𝑋 ∈ (𝐴 ∩ 𝐵) ∧ (𝐺‘𝑋) = (𝐾‘𝑋) ∧ ∀𝑥 ∈ (ran 𝐺 ∩ ran 𝐾)(𝐹‘𝑥) = (𝐻‘𝑥))) → (𝐻‘(𝐾‘𝑋)) = (𝐻‘(𝐺‘𝑋)))
18		id 22	. . . . . . . . . . . 12 ⊢ (𝐺 Fn 𝐴 → 𝐺 Fn 𝐴)
19		fnfvelrn 6264	. . . . . . . . . . . 12 ⊢ ((𝐺 Fn 𝐴 ∧ 𝑋 ∈ 𝐴) → (𝐺‘𝑋) ∈ ran 𝐺)
20	18, 4, 19	syl2anr 494	. . . . . . . . . . 11 ⊢ ((𝑋 ∈ (𝐴 ∩ 𝐵) ∧ 𝐺 Fn 𝐴) → (𝐺‘𝑋) ∈ ran 𝐺)
21	20	ex 449	. . . . . . . . . 10 ⊢ (𝑋 ∈ (𝐴 ∩ 𝐵) → (𝐺 Fn 𝐴 → (𝐺‘𝑋) ∈ ran 𝐺))
22		id 22	. . . . . . . . . . . 12 ⊢ (𝐾 Fn 𝐵 → 𝐾 Fn 𝐵)
23		fnfvelrn 6264	. . . . . . . . . . . 12 ⊢ ((𝐾 Fn 𝐵 ∧ 𝑋 ∈ 𝐵) → (𝐾‘𝑋) ∈ ran 𝐾)
24	22, 10, 23	syl2anr 494	. . . . . . . . . . 11 ⊢ ((𝑋 ∈ (𝐴 ∩ 𝐵) ∧ 𝐾 Fn 𝐵) → (𝐾‘𝑋) ∈ ran 𝐾)
25	24	ex 449	. . . . . . . . . 10 ⊢ (𝑋 ∈ (𝐴 ∩ 𝐵) → (𝐾 Fn 𝐵 → (𝐾‘𝑋) ∈ ran 𝐾))
26	21, 25	anim12d 584	. . . . . . . . 9 ⊢ (𝑋 ∈ (𝐴 ∩ 𝐵) → ((𝐺 Fn 𝐴 ∧ 𝐾 Fn 𝐵) → ((𝐺‘𝑋) ∈ ran 𝐺 ∧ (𝐾‘𝑋) ∈ ran 𝐾)))
27		eleq1 2676	. . . . . . . . . . . 12 ⊢ ((𝐾‘𝑋) = (𝐺‘𝑋) → ((𝐾‘𝑋) ∈ ran 𝐾 ↔ (𝐺‘𝑋) ∈ ran 𝐾))
28	27	eqcoms 2618	. . . . . . . . . . 11 ⊢ ((𝐺‘𝑋) = (𝐾‘𝑋) → ((𝐾‘𝑋) ∈ ran 𝐾 ↔ (𝐺‘𝑋) ∈ ran 𝐾))
29	28	anbi2d 736	. . . . . . . . . 10 ⊢ ((𝐺‘𝑋) = (𝐾‘𝑋) → (((𝐺‘𝑋) ∈ ran 𝐺 ∧ (𝐾‘𝑋) ∈ ran 𝐾) ↔ ((𝐺‘𝑋) ∈ ran 𝐺 ∧ (𝐺‘𝑋) ∈ ran 𝐾)))
30		elin 3758	. . . . . . . . . . 11 ⊢ ((𝐺‘𝑋) ∈ (ran 𝐺 ∩ ran 𝐾) ↔ ((𝐺‘𝑋) ∈ ran 𝐺 ∧ (𝐺‘𝑋) ∈ ran 𝐾))
31	30	biimpri 217	. . . . . . . . . 10 ⊢ (((𝐺‘𝑋) ∈ ran 𝐺 ∧ (𝐺‘𝑋) ∈ ran 𝐾) → (𝐺‘𝑋) ∈ (ran 𝐺 ∩ ran 𝐾))
32	29, 31	syl6bi 242	. . . . . . . . 9 ⊢ ((𝐺‘𝑋) = (𝐾‘𝑋) → (((𝐺‘𝑋) ∈ ran 𝐺 ∧ (𝐾‘𝑋) ∈ ran 𝐾) → (𝐺‘𝑋) ∈ (ran 𝐺 ∩ ran 𝐾)))
33	26, 32	sylan9 687	. . . . . . . 8 ⊢ ((𝑋 ∈ (𝐴 ∩ 𝐵) ∧ (𝐺‘𝑋) = (𝐾‘𝑋)) → ((𝐺 Fn 𝐴 ∧ 𝐾 Fn 𝐵) → (𝐺‘𝑋) ∈ (ran 𝐺 ∩ ran 𝐾)))
34		fveq2 6103	. . . . . . . . . . . 12 ⊢ (𝑥 = (𝐺‘𝑋) → (𝐹‘𝑥) = (𝐹‘(𝐺‘𝑋)))
35		fveq2 6103	. . . . . . . . . . . 12 ⊢ (𝑥 = (𝐺‘𝑋) → (𝐻‘𝑥) = (𝐻‘(𝐺‘𝑋)))
36	34, 35	eqeq12d 2625	. . . . . . . . . . 11 ⊢ (𝑥 = (𝐺‘𝑋) → ((𝐹‘𝑥) = (𝐻‘𝑥) ↔ (𝐹‘(𝐺‘𝑋)) = (𝐻‘(𝐺‘𝑋))))
37	36	rspcva 3280	. . . . . . . . . 10 ⊢ (((𝐺‘𝑋) ∈ (ran 𝐺 ∩ ran 𝐾) ∧ ∀𝑥 ∈ (ran 𝐺 ∩ ran 𝐾)(𝐹‘𝑥) = (𝐻‘𝑥)) → (𝐹‘(𝐺‘𝑋)) = (𝐻‘(𝐺‘𝑋)))
38	37	eqcomd 2616	. . . . . . . . 9 ⊢ (((𝐺‘𝑋) ∈ (ran 𝐺 ∩ ran 𝐾) ∧ ∀𝑥 ∈ (ran 𝐺 ∩ ran 𝐾)(𝐹‘𝑥) = (𝐻‘𝑥)) → (𝐻‘(𝐺‘𝑋)) = (𝐹‘(𝐺‘𝑋)))
39	38	ex 449	. . . . . . . 8 ⊢ ((𝐺‘𝑋) ∈ (ran 𝐺 ∩ ran 𝐾) → (∀𝑥 ∈ (ran 𝐺 ∩ ran 𝐾)(𝐹‘𝑥) = (𝐻‘𝑥) → (𝐻‘(𝐺‘𝑋)) = (𝐹‘(𝐺‘𝑋))))
40	33, 39	syl6 34	. . . . . . 7 ⊢ ((𝑋 ∈ (𝐴 ∩ 𝐵) ∧ (𝐺‘𝑋) = (𝐾‘𝑋)) → ((𝐺 Fn 𝐴 ∧ 𝐾 Fn 𝐵) → (∀𝑥 ∈ (ran 𝐺 ∩ ran 𝐾)(𝐹‘𝑥) = (𝐻‘𝑥) → (𝐻‘(𝐺‘𝑋)) = (𝐹‘(𝐺‘𝑋)))))
41	40	com23 84	. . . . . 6 ⊢ ((𝑋 ∈ (𝐴 ∩ 𝐵) ∧ (𝐺‘𝑋) = (𝐾‘𝑋)) → (∀𝑥 ∈ (ran 𝐺 ∩ ran 𝐾)(𝐹‘𝑥) = (𝐻‘𝑥) → ((𝐺 Fn 𝐴 ∧ 𝐾 Fn 𝐵) → (𝐻‘(𝐺‘𝑋)) = (𝐹‘(𝐺‘𝑋)))))
42	41	3impia 1253	. . . . 5 ⊢ ((𝑋 ∈ (𝐴 ∩ 𝐵) ∧ (𝐺‘𝑋) = (𝐾‘𝑋) ∧ ∀𝑥 ∈ (ran 𝐺 ∩ ran 𝐾)(𝐹‘𝑥) = (𝐻‘𝑥)) → ((𝐺 Fn 𝐴 ∧ 𝐾 Fn 𝐵) → (𝐻‘(𝐺‘𝑋)) = (𝐹‘(𝐺‘𝑋))))
43	42	impcom 445	. . . 4 ⊢ (((𝐺 Fn 𝐴 ∧ 𝐾 Fn 𝐵) ∧ (𝑋 ∈ (𝐴 ∩ 𝐵) ∧ (𝐺‘𝑋) = (𝐾‘𝑋) ∧ ∀𝑥 ∈ (ran 𝐺 ∩ ran 𝐾)(𝐹‘𝑥) = (𝐻‘𝑥))) → (𝐻‘(𝐺‘𝑋)) = (𝐹‘(𝐺‘𝑋)))
44	13, 17, 43	3eqtrrd 2649	. . 3 ⊢ (((𝐺 Fn 𝐴 ∧ 𝐾 Fn 𝐵) ∧ (𝑋 ∈ (𝐴 ∩ 𝐵) ∧ (𝐺‘𝑋) = (𝐾‘𝑋) ∧ ∀𝑥 ∈ (ran 𝐺 ∩ ran 𝐾)(𝐹‘𝑥) = (𝐻‘𝑥))) → (𝐹‘(𝐺‘𝑋)) = ((𝐻 ∘ 𝐾)‘𝑋))
45	7, 44	eqtrd 2644	. 2 ⊢ (((𝐺 Fn 𝐴 ∧ 𝐾 Fn 𝐵) ∧ (𝑋 ∈ (𝐴 ∩ 𝐵) ∧ (𝐺‘𝑋) = (𝐾‘𝑋) ∧ ∀𝑥 ∈ (ran 𝐺 ∩ ran 𝐾)(𝐹‘𝑥) = (𝐻‘𝑥))) → ((𝐹 ∘ 𝐺)‘𝑋) = ((𝐻 ∘ 𝐾)‘𝑋))
46	45	ex 449	1 ⊢ ((𝐺 Fn 𝐴 ∧ 𝐾 Fn 𝐵) → ((𝑋 ∈ (𝐴 ∩ 𝐵) ∧ (𝐺‘𝑋) = (𝐾‘𝑋) ∧ ∀𝑥 ∈ (ran 𝐺 ∩ ran 𝐾)(𝐹‘𝑥) = (𝐻‘𝑥)) → ((𝐹 ∘ 𝐺)‘𝑋) = ((𝐻 ∘ 𝐾)‘𝑋)))

Syntax hints:   → wi 4   ↔ wb 195   ∧ wa 383   ∧ w3a 1031   = wceq 1475   ∈ wcel 1977  ∀wral 2896   ∩ cin 3539  ran crn 5039   ∘ ccom 5042   Fn wfn 5799  ‘cfv 5804

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1713  ax-4 1728  ax-5 1827  ax-6 1875  ax-7 1922  ax-8 1979  ax-9 1986  ax-10 2006  ax-11 2021  ax-12 2034  ax-13 2234  ax-ext 2590  ax-sep 4709  ax-nul 4717  ax-pow 4769  ax-pr 4833

This theorem depends on definitions:  df-bi 196  df-or 384  df-an 385  df-3an 1033  df-tru 1478  df-ex 1696  df-nf 1701  df-sb 1868  df-eu 2462  df-mo 2463  df-clab 2597  df-cleq 2603  df-clel 2606  df-nfc 2740  df-ne 2782  df-ral 2901  df-rex 2902  df-rab 2905  df-v 3175  df-sbc 3403  df-dif 3543  df-un 3545  df-in 3547  df-ss 3554  df-nul 3875  df-if 4037  df-sn 4126  df-pr 4128  df-op 4132  df-uni 4373  df-br 4584  df-opab 4644  df-id 4953  df-xp 5044  df-rel 5045  df-cnv 5046  df-co 5047  df-dm 5048  df-rn 5049  df-res 5050  df-ima 5051  df-iota 5768  df-fun 5806  df-fn 5807  df-fv 5812

This theorem is referenced by:  fvcosymgeq  17672