Theorem preqsnOLD 4332

Description: Obsolete proof of preqsn 4331 as of 23-Jul-2021. (Contributed by NM, 3-Jun-2008.) (New usage is discouraged.) (Proof modification is discouraged.)

Hypotheses

Ref	Expression
preqsn.1	⊢ 𝐴 ∈ V
preqsn.2	⊢ 𝐵 ∈ V
preqsn.3	⊢ 𝐶 ∈ V

Assertion

Ref	Expression
preqsnOLD	⊢ ({𝐴, 𝐵} = {𝐶} ↔ (𝐴 = 𝐵 ∧ 𝐵 = 𝐶))

Proof of Theorem preqsnOLD

Step	Hyp	Ref	Expression
1		dfsn2 4138	. . 3 ⊢ {𝐶} = {𝐶, 𝐶}
2	1	eqeq2i 2622	. 2 ⊢ ({𝐴, 𝐵} = {𝐶} ↔ {𝐴, 𝐵} = {𝐶, 𝐶})
3		preqsn.1	. . . 4 ⊢ 𝐴 ∈ V
4		preqsn.2	. . . 4 ⊢ 𝐵 ∈ V
5		preqsn.3	. . . 4 ⊢ 𝐶 ∈ V
6	3, 4, 5, 5	preq12b 4322	. . 3 ⊢ ({𝐴, 𝐵} = {𝐶, 𝐶} ↔ ((𝐴 = 𝐶 ∧ 𝐵 = 𝐶) ∨ (𝐴 = 𝐶 ∧ 𝐵 = 𝐶)))
7		oridm 535	. . . 4 ⊢ (((𝐴 = 𝐶 ∧ 𝐵 = 𝐶) ∨ (𝐴 = 𝐶 ∧ 𝐵 = 𝐶)) ↔ (𝐴 = 𝐶 ∧ 𝐵 = 𝐶))
8		eqtr3 2631	. . . . . 6 ⊢ ((𝐴 = 𝐶 ∧ 𝐵 = 𝐶) → 𝐴 = 𝐵)
9		simpr 476	. . . . . 6 ⊢ ((𝐴 = 𝐶 ∧ 𝐵 = 𝐶) → 𝐵 = 𝐶)
10	8, 9	jca 553	. . . . 5 ⊢ ((𝐴 = 𝐶 ∧ 𝐵 = 𝐶) → (𝐴 = 𝐵 ∧ 𝐵 = 𝐶))
11		eqtr 2629	. . . . . 6 ⊢ ((𝐴 = 𝐵 ∧ 𝐵 = 𝐶) → 𝐴 = 𝐶)
12		simpr 476	. . . . . 6 ⊢ ((𝐴 = 𝐵 ∧ 𝐵 = 𝐶) → 𝐵 = 𝐶)
13	11, 12	jca 553	. . . . 5 ⊢ ((𝐴 = 𝐵 ∧ 𝐵 = 𝐶) → (𝐴 = 𝐶 ∧ 𝐵 = 𝐶))
14	10, 13	impbii 198	. . . 4 ⊢ ((𝐴 = 𝐶 ∧ 𝐵 = 𝐶) ↔ (𝐴 = 𝐵 ∧ 𝐵 = 𝐶))
15	7, 14	bitri 263	. . 3 ⊢ (((𝐴 = 𝐶 ∧ 𝐵 = 𝐶) ∨ (𝐴 = 𝐶 ∧ 𝐵 = 𝐶)) ↔ (𝐴 = 𝐵 ∧ 𝐵 = 𝐶))
16	6, 15	bitri 263	. 2 ⊢ ({𝐴, 𝐵} = {𝐶, 𝐶} ↔ (𝐴 = 𝐵 ∧ 𝐵 = 𝐶))
17	2, 16	bitri 263	1 ⊢ ({𝐴, 𝐵} = {𝐶} ↔ (𝐴 = 𝐵 ∧ 𝐵 = 𝐶))

Syntax hints:   ↔ wb 195   ∨ wo 382   ∧ wa 383   = wceq 1475   ∈ wcel 1977  Vcvv 3173  {csn 4125  {cpr 4127

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1713  ax-4 1728  ax-5 1827  ax-6 1875  ax-7 1922  ax-10 2006  ax-11 2021  ax-12 2034  ax-13 2234  ax-ext 2590

This theorem depends on definitions:  df-bi 196  df-or 384  df-an 385  df-tru 1478  df-ex 1696  df-nf 1701  df-sb 1868  df-clab 2597  df-cleq 2603  df-clel 2606  df-nfc 2740  df-v 3175  df-un 3545  df-sn 4126  df-pr 4128

This theorem is referenced by: (None)