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Theorem errel 7638
Description: An equivalence relation is a relation. (Contributed by Mario Carneiro, 12-Aug-2015.)
Assertion
Ref Expression
errel (𝑅 Er 𝐴 → Rel 𝑅)

Proof of Theorem errel
StepHypRef Expression
1 df-er 7629 . 2 (𝑅 Er 𝐴 ↔ (Rel 𝑅 ∧ dom 𝑅 = 𝐴 ∧ (𝑅 ∪ (𝑅𝑅)) ⊆ 𝑅))
21simp1bi 1069 1 (𝑅 Er 𝐴 → Rel 𝑅)
Colors of variables: wff setvar class
Syntax hints:  wi 4   = wceq 1475  cun 3538  wss 3540  ccnv 5037  dom cdm 5038  ccom 5042  Rel wrel 5043   Er wer 7626
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This theorem depends on definitions:  df-bi 196  df-an 385  df-3an 1033  df-er 7629
This theorem is referenced by:  ercl  7640  ersym  7641  ertr  7644  ercnv  7650  erssxp  7652  erth  7678  iiner  7706  frgpuplem  18008  ismntop  29398  topfneec  31520  prter3  33185
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