Theorem wl-equsb3 32516

Description: equsb3 2420 with a distinctor. (Contributed by Wolf Lammen, 27-Jun-2019.)

Assertion

Ref	Expression
wl-equsb3	⊢ (¬ ∀𝑦 𝑦 = 𝑧 → ([𝑥 / 𝑦]𝑦 = 𝑧 ↔ 𝑥 = 𝑧))

Proof of Theorem wl-equsb3

Dummy variable 𝑤 is distinct from all other variables.

Step	Hyp	Ref	Expression
1		nfv 1830	. . 3 ⊢ Ⅎ𝑤 ¬ ∀𝑦 𝑦 = 𝑧
2		nfna1 2016	. . . 4 ⊢ Ⅎ𝑦 ¬ ∀𝑦 𝑦 = 𝑧
3		nfeqf2 2285	. . . 4 ⊢ (¬ ∀𝑦 𝑦 = 𝑧 → Ⅎ𝑦 𝑤 = 𝑧)
4		equequ1 1939	. . . . 5 ⊢ (𝑦 = 𝑤 → (𝑦 = 𝑧 ↔ 𝑤 = 𝑧))
5	4	a1i 11	. . . 4 ⊢ (¬ ∀𝑦 𝑦 = 𝑧 → (𝑦 = 𝑤 → (𝑦 = 𝑧 ↔ 𝑤 = 𝑧)))
6	2, 3, 5	sbied 2397	. . 3 ⊢ (¬ ∀𝑦 𝑦 = 𝑧 → ([𝑤 / 𝑦]𝑦 = 𝑧 ↔ 𝑤 = 𝑧))
7	1, 6	sbbid 2391	. 2 ⊢ (¬ ∀𝑦 𝑦 = 𝑧 → ([𝑥 / 𝑤][𝑤 / 𝑦]𝑦 = 𝑧 ↔ [𝑥 / 𝑤]𝑤 = 𝑧))
8		sbcom3 2399	. . 3 ⊢ ([𝑥 / 𝑤][𝑤 / 𝑦]𝑦 = 𝑧 ↔ [𝑥 / 𝑤][𝑥 / 𝑦]𝑦 = 𝑧)
9		nfv 1830	. . . 4 ⊢ Ⅎ𝑤[𝑥 / 𝑦]𝑦 = 𝑧
10	9	sbf 2368	. . 3 ⊢ ([𝑥 / 𝑤][𝑥 / 𝑦]𝑦 = 𝑧 ↔ [𝑥 / 𝑦]𝑦 = 𝑧)
11	8, 10	bitri 263	. 2 ⊢ ([𝑥 / 𝑤][𝑤 / 𝑦]𝑦 = 𝑧 ↔ [𝑥 / 𝑦]𝑦 = 𝑧)
12		equsb3 2420	. 2 ⊢ ([𝑥 / 𝑤]𝑤 = 𝑧 ↔ 𝑥 = 𝑧)
13	7, 11, 12	3bitr3g 301	1 ⊢ (¬ ∀𝑦 𝑦 = 𝑧 → ([𝑥 / 𝑦]𝑦 = 𝑧 ↔ 𝑥 = 𝑧))

Syntax hints:  ¬ wn 3   → wi 4   ↔ wb 195  ∀wal 1473  [wsb 1867

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1713  ax-4 1728  ax-5 1827  ax-6 1875  ax-7 1922  ax-10 2006  ax-12 2034  ax-13 2234

This theorem depends on definitions:  df-bi 196  df-or 384  df-an 385  df-tru 1478  df-ex 1696  df-nf 1701  df-sb 1868

This theorem is referenced by: (None)