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Theorem rp-fakeoranass 36878
Description: A special case where a mixture of or and and appears to conform to a mixed associative law. (Contributed by Richard Penner, 29-Feb-2020.)
Assertion
Ref Expression
rp-fakeoranass ((𝜑𝜒) ↔ (((𝜑𝜓) ∧ 𝜒) ↔ (𝜑 ∨ (𝜓𝜒))))

Proof of Theorem rp-fakeoranass
StepHypRef Expression
1 rp-fakeanorass 36877 . 2 ((𝜑𝜒) ↔ (((𝜒𝜓) ∨ 𝜑) ↔ (𝜒 ∧ (𝜓𝜑))))
2 bicom 211 . . 3 ((((𝜒𝜓) ∨ 𝜑) ↔ (𝜒 ∧ (𝜓𝜑))) ↔ ((𝜒 ∧ (𝜓𝜑)) ↔ ((𝜒𝜓) ∨ 𝜑)))
3 ancom 465 . . . . 5 ((𝜒 ∧ (𝜓𝜑)) ↔ ((𝜓𝜑) ∧ 𝜒))
4 orcom 401 . . . . . 6 ((𝜓𝜑) ↔ (𝜑𝜓))
54anbi1i 727 . . . . 5 (((𝜓𝜑) ∧ 𝜒) ↔ ((𝜑𝜓) ∧ 𝜒))
63, 5bitri 263 . . . 4 ((𝜒 ∧ (𝜓𝜑)) ↔ ((𝜑𝜓) ∧ 𝜒))
7 orcom 401 . . . . 5 (((𝜒𝜓) ∨ 𝜑) ↔ (𝜑 ∨ (𝜒𝜓)))
8 ancom 465 . . . . . 6 ((𝜒𝜓) ↔ (𝜓𝜒))
98orbi2i 540 . . . . 5 ((𝜑 ∨ (𝜒𝜓)) ↔ (𝜑 ∨ (𝜓𝜒)))
107, 9bitri 263 . . . 4 (((𝜒𝜓) ∨ 𝜑) ↔ (𝜑 ∨ (𝜓𝜒)))
116, 10bibi12i 328 . . 3 (((𝜒 ∧ (𝜓𝜑)) ↔ ((𝜒𝜓) ∨ 𝜑)) ↔ (((𝜑𝜓) ∧ 𝜒) ↔ (𝜑 ∨ (𝜓𝜒))))
122, 11bitri 263 . 2 ((((𝜒𝜓) ∨ 𝜑) ↔ (𝜒 ∧ (𝜓𝜑))) ↔ (((𝜑𝜓) ∧ 𝜒) ↔ (𝜑 ∨ (𝜓𝜒))))
131, 12bitri 263 1 ((𝜑𝜒) ↔ (((𝜑𝜓) ∧ 𝜒) ↔ (𝜑 ∨ (𝜓𝜒))))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 195  wo 382  wa 383
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This theorem depends on definitions:  df-bi 196  df-or 384  df-an 385
This theorem is referenced by: (None)
  Copyright terms: Public domain W3C validator