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Theorem reuxfrd 4819
Description: Transfer existential uniqueness from a variable 𝑥 to another variable 𝑦 contained in expression 𝐴. Use reuhypd 4821 to eliminate the second hypothesis. (Contributed by NM, 16-Jan-2012.)
Hypotheses
Ref Expression
reuxfrd.1 ((𝜑𝑦𝐵) → 𝐴𝐵)
reuxfrd.2 ((𝜑𝑥𝐵) → ∃!𝑦𝐵 𝑥 = 𝐴)
reuxfrd.3 (𝑥 = 𝐴 → (𝜓𝜒))
Assertion
Ref Expression
reuxfrd (𝜑 → (∃!𝑥𝐵 𝜓 ↔ ∃!𝑦𝐵 𝜒))
Distinct variable groups:   𝑥,𝑦,𝜑   𝜓,𝑦   𝜒,𝑥   𝑥,𝐴   𝑥,𝐵,𝑦
Allowed substitution hints:   𝜓(𝑥)   𝜒(𝑦)   𝐴(𝑦)

Proof of Theorem reuxfrd
StepHypRef Expression
1 reuxfrd.2 . . . . . 6 ((𝜑𝑥𝐵) → ∃!𝑦𝐵 𝑥 = 𝐴)
2 reurex 3137 . . . . . 6 (∃!𝑦𝐵 𝑥 = 𝐴 → ∃𝑦𝐵 𝑥 = 𝐴)
31, 2syl 17 . . . . 5 ((𝜑𝑥𝐵) → ∃𝑦𝐵 𝑥 = 𝐴)
43biantrurd 528 . . . 4 ((𝜑𝑥𝐵) → (𝜓 ↔ (∃𝑦𝐵 𝑥 = 𝐴𝜓)))
5 r19.41v 3070 . . . . 5 (∃𝑦𝐵 (𝑥 = 𝐴𝜓) ↔ (∃𝑦𝐵 𝑥 = 𝐴𝜓))
6 reuxfrd.3 . . . . . . 7 (𝑥 = 𝐴 → (𝜓𝜒))
76pm5.32i 667 . . . . . 6 ((𝑥 = 𝐴𝜓) ↔ (𝑥 = 𝐴𝜒))
87rexbii 3023 . . . . 5 (∃𝑦𝐵 (𝑥 = 𝐴𝜓) ↔ ∃𝑦𝐵 (𝑥 = 𝐴𝜒))
95, 8bitr3i 265 . . . 4 ((∃𝑦𝐵 𝑥 = 𝐴𝜓) ↔ ∃𝑦𝐵 (𝑥 = 𝐴𝜒))
104, 9syl6bb 275 . . 3 ((𝜑𝑥𝐵) → (𝜓 ↔ ∃𝑦𝐵 (𝑥 = 𝐴𝜒)))
1110reubidva 3102 . 2 (𝜑 → (∃!𝑥𝐵 𝜓 ↔ ∃!𝑥𝐵𝑦𝐵 (𝑥 = 𝐴𝜒)))
12 reuxfrd.1 . . 3 ((𝜑𝑦𝐵) → 𝐴𝐵)
13 reurmo 3138 . . . 4 (∃!𝑦𝐵 𝑥 = 𝐴 → ∃*𝑦𝐵 𝑥 = 𝐴)
141, 13syl 17 . . 3 ((𝜑𝑥𝐵) → ∃*𝑦𝐵 𝑥 = 𝐴)
1512, 14reuxfr2d 4817 . 2 (𝜑 → (∃!𝑥𝐵𝑦𝐵 (𝑥 = 𝐴𝜒) ↔ ∃!𝑦𝐵 𝜒))
1611, 15bitrd 267 1 (𝜑 → (∃!𝑥𝐵 𝜓 ↔ ∃!𝑦𝐵 𝜒))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 195  wa 383   = wceq 1475  wcel 1977  wrex 2897  ∃!wreu 2898  ∃*wrmo 2899
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1713  ax-4 1728  ax-5 1827  ax-6 1875  ax-7 1922  ax-10 2006  ax-11 2021  ax-12 2034  ax-13 2234  ax-ext 2590
This theorem depends on definitions:  df-bi 196  df-or 384  df-an 385  df-tru 1478  df-ex 1696  df-nf 1701  df-sb 1868  df-eu 2462  df-mo 2463  df-clab 2597  df-cleq 2603  df-clel 2606  df-ral 2901  df-rex 2902  df-reu 2903  df-rmo 2904  df-v 3175
This theorem is referenced by:  reuxfr  4820  riotaxfrd  6541
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