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Type | Label | Description |
---|---|---|
Statement | ||
Theorem | mpidan 701 | A deduction which "stacks" a hypothesis. (Contributed by Stanislas Polu, 9-Mar-2020.) (Proof shortened by Wolf Lammen, 28-Mar-2021.) |
⊢ (𝜑 → 𝜒) & ⊢ (((𝜑 ∧ 𝜓) ∧ 𝜒) → 𝜃) ⇒ ⊢ ((𝜑 ∧ 𝜓) → 𝜃) | ||
Theorem | mpan 702 | An inference based on modus ponens. (Contributed by NM, 30-Aug-1993.) (Proof shortened by Wolf Lammen, 7-Apr-2013.) |
⊢ 𝜑 & ⊢ ((𝜑 ∧ 𝜓) → 𝜒) ⇒ ⊢ (𝜓 → 𝜒) | ||
Theorem | mpan2 703 | An inference based on modus ponens. (Contributed by NM, 16-Sep-1993.) (Proof shortened by Wolf Lammen, 19-Nov-2012.) |
⊢ 𝜓 & ⊢ ((𝜑 ∧ 𝜓) → 𝜒) ⇒ ⊢ (𝜑 → 𝜒) | ||
Theorem | mp2an 704 | An inference based on modus ponens. (Contributed by NM, 13-Apr-1995.) |
⊢ 𝜑 & ⊢ 𝜓 & ⊢ ((𝜑 ∧ 𝜓) → 𝜒) ⇒ ⊢ 𝜒 | ||
Theorem | mp4an 705 | An inference based on modus ponens. (Contributed by Jeff Madsen, 15-Jun-2010.) |
⊢ 𝜑 & ⊢ 𝜓 & ⊢ 𝜒 & ⊢ 𝜃 & ⊢ (((𝜑 ∧ 𝜓) ∧ (𝜒 ∧ 𝜃)) → 𝜏) ⇒ ⊢ 𝜏 | ||
Theorem | mpan2d 706 | A deduction based on modus ponens. (Contributed by NM, 12-Dec-2004.) |
⊢ (𝜑 → 𝜒) & ⊢ (𝜑 → ((𝜓 ∧ 𝜒) → 𝜃)) ⇒ ⊢ (𝜑 → (𝜓 → 𝜃)) | ||
Theorem | mpand 707 | A deduction based on modus ponens. (Contributed by NM, 12-Dec-2004.) (Proof shortened by Wolf Lammen, 7-Apr-2013.) |
⊢ (𝜑 → 𝜓) & ⊢ (𝜑 → ((𝜓 ∧ 𝜒) → 𝜃)) ⇒ ⊢ (𝜑 → (𝜒 → 𝜃)) | ||
Theorem | mpani 708 | An inference based on modus ponens. (Contributed by NM, 10-Apr-1994.) (Proof shortened by Wolf Lammen, 19-Nov-2012.) |
⊢ 𝜓 & ⊢ (𝜑 → ((𝜓 ∧ 𝜒) → 𝜃)) ⇒ ⊢ (𝜑 → (𝜒 → 𝜃)) | ||
Theorem | mpan2i 709 | An inference based on modus ponens. (Contributed by NM, 10-Apr-1994.) (Proof shortened by Wolf Lammen, 19-Nov-2012.) |
⊢ 𝜒 & ⊢ (𝜑 → ((𝜓 ∧ 𝜒) → 𝜃)) ⇒ ⊢ (𝜑 → (𝜓 → 𝜃)) | ||
Theorem | mp2ani 710 | An inference based on modus ponens. (Contributed by NM, 12-Dec-2004.) |
⊢ 𝜓 & ⊢ 𝜒 & ⊢ (𝜑 → ((𝜓 ∧ 𝜒) → 𝜃)) ⇒ ⊢ (𝜑 → 𝜃) | ||
Theorem | mp2and 711 | A deduction based on modus ponens. (Contributed by NM, 12-Dec-2004.) |
⊢ (𝜑 → 𝜓) & ⊢ (𝜑 → 𝜒) & ⊢ (𝜑 → ((𝜓 ∧ 𝜒) → 𝜃)) ⇒ ⊢ (𝜑 → 𝜃) | ||
Theorem | mpanl1 712 | An inference based on modus ponens. (Contributed by NM, 16-Aug-1994.) (Proof shortened by Wolf Lammen, 7-Apr-2013.) |
⊢ 𝜑 & ⊢ (((𝜑 ∧ 𝜓) ∧ 𝜒) → 𝜃) ⇒ ⊢ ((𝜓 ∧ 𝜒) → 𝜃) | ||
Theorem | mpanl2 713 | An inference based on modus ponens. (Contributed by NM, 16-Aug-1994.) (Proof shortened by Andrew Salmon, 7-May-2011.) |
⊢ 𝜓 & ⊢ (((𝜑 ∧ 𝜓) ∧ 𝜒) → 𝜃) ⇒ ⊢ ((𝜑 ∧ 𝜒) → 𝜃) | ||
Theorem | mpanl12 714 | An inference based on modus ponens. (Contributed by NM, 13-Jul-2005.) |
⊢ 𝜑 & ⊢ 𝜓 & ⊢ (((𝜑 ∧ 𝜓) ∧ 𝜒) → 𝜃) ⇒ ⊢ (𝜒 → 𝜃) | ||
Theorem | mpanr1 715 | An inference based on modus ponens. (Contributed by NM, 3-May-1994.) (Proof shortened by Andrew Salmon, 7-May-2011.) |
⊢ 𝜓 & ⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒)) → 𝜃) ⇒ ⊢ ((𝜑 ∧ 𝜒) → 𝜃) | ||
Theorem | mpanr2 716 | An inference based on modus ponens. (Contributed by NM, 3-May-1994.) (Proof shortened by Andrew Salmon, 7-May-2011.) (Proof shortened by Wolf Lammen, 7-Apr-2013.) |
⊢ 𝜒 & ⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒)) → 𝜃) ⇒ ⊢ ((𝜑 ∧ 𝜓) → 𝜃) | ||
Theorem | mpanr12 717 | An inference based on modus ponens. (Contributed by NM, 24-Jul-2009.) |
⊢ 𝜓 & ⊢ 𝜒 & ⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒)) → 𝜃) ⇒ ⊢ (𝜑 → 𝜃) | ||
Theorem | mpanlr1 718 | An inference based on modus ponens. (Contributed by NM, 30-Dec-2004.) (Proof shortened by Wolf Lammen, 7-Apr-2013.) |
⊢ 𝜓 & ⊢ (((𝜑 ∧ (𝜓 ∧ 𝜒)) ∧ 𝜃) → 𝜏) ⇒ ⊢ (((𝜑 ∧ 𝜒) ∧ 𝜃) → 𝜏) | ||
Theorem | pm5.74da 719 | Distribution of implication over biconditional (deduction rule). (Contributed by NM, 4-May-2007.) |
⊢ ((𝜑 ∧ 𝜓) → (𝜒 ↔ 𝜃)) ⇒ ⊢ (𝜑 → ((𝜓 → 𝜒) ↔ (𝜓 → 𝜃))) | ||
Theorem | pm4.45 720 | Theorem *4.45 of [WhiteheadRussell] p. 119. (Contributed by NM, 3-Jan-2005.) |
⊢ (𝜑 ↔ (𝜑 ∧ (𝜑 ∨ 𝜓))) | ||
Theorem | imdistan 721 | Distribution of implication with conjunction. (Contributed by NM, 31-May-1999.) (Proof shortened by Wolf Lammen, 6-Dec-2012.) |
⊢ ((𝜑 → (𝜓 → 𝜒)) ↔ ((𝜑 ∧ 𝜓) → (𝜑 ∧ 𝜒))) | ||
Theorem | imdistani 722 | Distribution of implication with conjunction. (Contributed by NM, 1-Aug-1994.) |
⊢ (𝜑 → (𝜓 → 𝜒)) ⇒ ⊢ ((𝜑 ∧ 𝜓) → (𝜑 ∧ 𝜒)) | ||
Theorem | imdistanri 723 | Distribution of implication with conjunction. (Contributed by NM, 8-Jan-2002.) |
⊢ (𝜑 → (𝜓 → 𝜒)) ⇒ ⊢ ((𝜓 ∧ 𝜑) → (𝜒 ∧ 𝜑)) | ||
Theorem | imdistand 724 | Distribution of implication with conjunction (deduction rule). (Contributed by NM, 27-Aug-2004.) |
⊢ (𝜑 → (𝜓 → (𝜒 → 𝜃))) ⇒ ⊢ (𝜑 → ((𝜓 ∧ 𝜒) → (𝜓 ∧ 𝜃))) | ||
Theorem | imdistanda 725 | Distribution of implication with conjunction (deduction version with conjoined antecedent). (Contributed by Jeff Madsen, 19-Jun-2011.) |
⊢ ((𝜑 ∧ 𝜓) → (𝜒 → 𝜃)) ⇒ ⊢ (𝜑 → ((𝜓 ∧ 𝜒) → (𝜓 ∧ 𝜃))) | ||
Theorem | anbi2i 726 | Introduce a left conjunct to both sides of a logical equivalence. (Contributed by NM, 3-Jan-1993.) (Proof shortened by Wolf Lammen, 16-Nov-2013.) |
⊢ (𝜑 ↔ 𝜓) ⇒ ⊢ ((𝜒 ∧ 𝜑) ↔ (𝜒 ∧ 𝜓)) | ||
Theorem | anbi1i 727 | Introduce a right conjunct to both sides of a logical equivalence. (Contributed by NM, 12-Mar-1993.) (Proof shortened by Wolf Lammen, 16-Nov-2013.) |
⊢ (𝜑 ↔ 𝜓) ⇒ ⊢ ((𝜑 ∧ 𝜒) ↔ (𝜓 ∧ 𝜒)) | ||
Theorem | anbi2ci 728 | Variant of anbi2i 726 with commutation. (Contributed by Jonathan Ben-Naim, 3-Jun-2011.) (Proof shortened by Andrew Salmon, 14-Jun-2011.) |
⊢ (𝜑 ↔ 𝜓) ⇒ ⊢ ((𝜑 ∧ 𝜒) ↔ (𝜒 ∧ 𝜓)) | ||
Theorem | anbi12i 729 | Conjoin both sides of two equivalences. (Contributed by NM, 12-Mar-1993.) |
⊢ (𝜑 ↔ 𝜓) & ⊢ (𝜒 ↔ 𝜃) ⇒ ⊢ ((𝜑 ∧ 𝜒) ↔ (𝜓 ∧ 𝜃)) | ||
Theorem | anbi12ci 730 | Variant of anbi12i 729 with commutation. (Contributed by Jonathan Ben-Naim, 3-Jun-2011.) |
⊢ (𝜑 ↔ 𝜓) & ⊢ (𝜒 ↔ 𝜃) ⇒ ⊢ ((𝜑 ∧ 𝜒) ↔ (𝜃 ∧ 𝜓)) | ||
Theorem | syldanl 731 | A syllogism deduction with conjoined antecedents. (Contributed by Jeff Madsen, 20-Jun-2011.) |
⊢ ((𝜑 ∧ 𝜓) → 𝜒) & ⊢ (((𝜑 ∧ 𝜒) ∧ 𝜃) → 𝜏) ⇒ ⊢ (((𝜑 ∧ 𝜓) ∧ 𝜃) → 𝜏) | ||
Theorem | sylan9bb 732 | Nested syllogism inference conjoining dissimilar antecedents. (Contributed by NM, 4-Mar-1995.) |
⊢ (𝜑 → (𝜓 ↔ 𝜒)) & ⊢ (𝜃 → (𝜒 ↔ 𝜏)) ⇒ ⊢ ((𝜑 ∧ 𝜃) → (𝜓 ↔ 𝜏)) | ||
Theorem | sylan9bbr 733 | Nested syllogism inference conjoining dissimilar antecedents. (Contributed by NM, 4-Mar-1995.) |
⊢ (𝜑 → (𝜓 ↔ 𝜒)) & ⊢ (𝜃 → (𝜒 ↔ 𝜏)) ⇒ ⊢ ((𝜃 ∧ 𝜑) → (𝜓 ↔ 𝜏)) | ||
Theorem | orbi2d 734 | Deduction adding a left disjunct to both sides of a logical equivalence. (Contributed by NM, 21-Jun-1993.) |
⊢ (𝜑 → (𝜓 ↔ 𝜒)) ⇒ ⊢ (𝜑 → ((𝜃 ∨ 𝜓) ↔ (𝜃 ∨ 𝜒))) | ||
Theorem | orbi1d 735 | Deduction adding a right disjunct to both sides of a logical equivalence. (Contributed by NM, 21-Jun-1993.) |
⊢ (𝜑 → (𝜓 ↔ 𝜒)) ⇒ ⊢ (𝜑 → ((𝜓 ∨ 𝜃) ↔ (𝜒 ∨ 𝜃))) | ||
Theorem | anbi2d 736 | Deduction adding a left conjunct to both sides of a logical equivalence. (Contributed by NM, 11-May-1993.) (Proof shortened by Wolf Lammen, 16-Nov-2013.) |
⊢ (𝜑 → (𝜓 ↔ 𝜒)) ⇒ ⊢ (𝜑 → ((𝜃 ∧ 𝜓) ↔ (𝜃 ∧ 𝜒))) | ||
Theorem | anbi1d 737 | Deduction adding a right conjunct to both sides of a logical equivalence. (Contributed by NM, 11-May-1993.) (Proof shortened by Wolf Lammen, 16-Nov-2013.) |
⊢ (𝜑 → (𝜓 ↔ 𝜒)) ⇒ ⊢ (𝜑 → ((𝜓 ∧ 𝜃) ↔ (𝜒 ∧ 𝜃))) | ||
Theorem | orbi1 738 | Theorem *4.37 of [WhiteheadRussell] p. 118. (Contributed by NM, 3-Jan-2005.) |
⊢ ((𝜑 ↔ 𝜓) → ((𝜑 ∨ 𝜒) ↔ (𝜓 ∨ 𝜒))) | ||
Theorem | anbi1 739 | Introduce a right conjunct to both sides of a logical equivalence. Theorem *4.36 of [WhiteheadRussell] p. 118. (Contributed by NM, 3-Jan-2005.) |
⊢ ((𝜑 ↔ 𝜓) → ((𝜑 ∧ 𝜒) ↔ (𝜓 ∧ 𝜒))) | ||
Theorem | anbi2 740 | Introduce a left conjunct to both sides of a logical equivalence. (Contributed by NM, 16-Nov-2013.) |
⊢ ((𝜑 ↔ 𝜓) → ((𝜒 ∧ 𝜑) ↔ (𝜒 ∧ 𝜓))) | ||
Theorem | bitr 741 | Theorem *4.22 of [WhiteheadRussell] p. 117. (Contributed by NM, 3-Jan-2005.) |
⊢ (((𝜑 ↔ 𝜓) ∧ (𝜓 ↔ 𝜒)) → (𝜑 ↔ 𝜒)) | ||
Theorem | orbi12d 742 | Deduction joining two equivalences to form equivalence of disjunctions. (Contributed by NM, 21-Jun-1993.) |
⊢ (𝜑 → (𝜓 ↔ 𝜒)) & ⊢ (𝜑 → (𝜃 ↔ 𝜏)) ⇒ ⊢ (𝜑 → ((𝜓 ∨ 𝜃) ↔ (𝜒 ∨ 𝜏))) | ||
Theorem | anbi12d 743 | Deduction joining two equivalences to form equivalence of conjunctions. (Contributed by NM, 26-May-1993.) |
⊢ (𝜑 → (𝜓 ↔ 𝜒)) & ⊢ (𝜑 → (𝜃 ↔ 𝜏)) ⇒ ⊢ (𝜑 → ((𝜓 ∧ 𝜃) ↔ (𝜒 ∧ 𝜏))) | ||
Theorem | pm5.3 744 | Theorem *5.3 of [WhiteheadRussell] p. 125. (Contributed by NM, 3-Jan-2005.) (Proof shortened by Andrew Salmon, 7-May-2011.) |
⊢ (((𝜑 ∧ 𝜓) → 𝜒) ↔ ((𝜑 ∧ 𝜓) → (𝜑 ∧ 𝜒))) | ||
Theorem | pm5.61 745 | Theorem *5.61 of [WhiteheadRussell] p. 125. (Contributed by NM, 3-Jan-2005.) (Proof shortened by Wolf Lammen, 30-Jun-2013.) |
⊢ (((𝜑 ∨ 𝜓) ∧ ¬ 𝜓) ↔ (𝜑 ∧ ¬ 𝜓)) | ||
Theorem | adantll 746 | Deduction adding a conjunct to antecedent. (Contributed by NM, 4-May-1994.) (Proof shortened by Wolf Lammen, 24-Nov-2012.) |
⊢ ((𝜑 ∧ 𝜓) → 𝜒) ⇒ ⊢ (((𝜃 ∧ 𝜑) ∧ 𝜓) → 𝜒) | ||
Theorem | adantlr 747 | Deduction adding a conjunct to antecedent. (Contributed by NM, 4-May-1994.) (Proof shortened by Wolf Lammen, 24-Nov-2012.) |
⊢ ((𝜑 ∧ 𝜓) → 𝜒) ⇒ ⊢ (((𝜑 ∧ 𝜃) ∧ 𝜓) → 𝜒) | ||
Theorem | adantrl 748 | Deduction adding a conjunct to antecedent. (Contributed by NM, 4-May-1994.) (Proof shortened by Wolf Lammen, 24-Nov-2012.) |
⊢ ((𝜑 ∧ 𝜓) → 𝜒) ⇒ ⊢ ((𝜑 ∧ (𝜃 ∧ 𝜓)) → 𝜒) | ||
Theorem | adantrr 749 | Deduction adding a conjunct to antecedent. (Contributed by NM, 4-May-1994.) (Proof shortened by Wolf Lammen, 24-Nov-2012.) |
⊢ ((𝜑 ∧ 𝜓) → 𝜒) ⇒ ⊢ ((𝜑 ∧ (𝜓 ∧ 𝜃)) → 𝜒) | ||
Theorem | adantlll 750 | Deduction adding a conjunct to antecedent. (Contributed by NM, 26-Dec-2004.) (Proof shortened by Wolf Lammen, 2-Dec-2012.) |
⊢ (((𝜑 ∧ 𝜓) ∧ 𝜒) → 𝜃) ⇒ ⊢ ((((𝜏 ∧ 𝜑) ∧ 𝜓) ∧ 𝜒) → 𝜃) | ||
Theorem | adantllr 751 | Deduction adding a conjunct to antecedent. (Contributed by NM, 26-Dec-2004.) (Proof shortened by Wolf Lammen, 4-Dec-2012.) |
⊢ (((𝜑 ∧ 𝜓) ∧ 𝜒) → 𝜃) ⇒ ⊢ ((((𝜑 ∧ 𝜏) ∧ 𝜓) ∧ 𝜒) → 𝜃) | ||
Theorem | adantlrl 752 | Deduction adding a conjunct to antecedent. (Contributed by NM, 26-Dec-2004.) (Proof shortened by Wolf Lammen, 4-Dec-2012.) |
⊢ (((𝜑 ∧ 𝜓) ∧ 𝜒) → 𝜃) ⇒ ⊢ (((𝜑 ∧ (𝜏 ∧ 𝜓)) ∧ 𝜒) → 𝜃) | ||
Theorem | adantlrr 753 | Deduction adding a conjunct to antecedent. (Contributed by NM, 26-Dec-2004.) (Proof shortened by Wolf Lammen, 4-Dec-2012.) |
⊢ (((𝜑 ∧ 𝜓) ∧ 𝜒) → 𝜃) ⇒ ⊢ (((𝜑 ∧ (𝜓 ∧ 𝜏)) ∧ 𝜒) → 𝜃) | ||
Theorem | adantrll 754 | Deduction adding a conjunct to antecedent. (Contributed by NM, 26-Dec-2004.) (Proof shortened by Wolf Lammen, 4-Dec-2012.) |
⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒)) → 𝜃) ⇒ ⊢ ((𝜑 ∧ ((𝜏 ∧ 𝜓) ∧ 𝜒)) → 𝜃) | ||
Theorem | adantrlr 755 | Deduction adding a conjunct to antecedent. (Contributed by NM, 26-Dec-2004.) (Proof shortened by Wolf Lammen, 4-Dec-2012.) |
⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒)) → 𝜃) ⇒ ⊢ ((𝜑 ∧ ((𝜓 ∧ 𝜏) ∧ 𝜒)) → 𝜃) | ||
Theorem | adantrrl 756 | Deduction adding a conjunct to antecedent. (Contributed by NM, 26-Dec-2004.) (Proof shortened by Wolf Lammen, 4-Dec-2012.) |
⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒)) → 𝜃) ⇒ ⊢ ((𝜑 ∧ (𝜓 ∧ (𝜏 ∧ 𝜒))) → 𝜃) | ||
Theorem | adantrrr 757 | Deduction adding a conjunct to antecedent. (Contributed by NM, 26-Dec-2004.) (Proof shortened by Wolf Lammen, 4-Dec-2012.) |
⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒)) → 𝜃) ⇒ ⊢ ((𝜑 ∧ (𝜓 ∧ (𝜒 ∧ 𝜏))) → 𝜃) | ||
Theorem | ad2antrr 758 | Deduction adding two conjuncts to antecedent. (Contributed by NM, 19-Oct-1999.) (Proof shortened by Wolf Lammen, 20-Nov-2012.) |
⊢ (𝜑 → 𝜓) ⇒ ⊢ (((𝜑 ∧ 𝜒) ∧ 𝜃) → 𝜓) | ||
Theorem | ad2antlr 759 | Deduction adding two conjuncts to antecedent. (Contributed by NM, 19-Oct-1999.) (Proof shortened by Wolf Lammen, 20-Nov-2012.) |
⊢ (𝜑 → 𝜓) ⇒ ⊢ (((𝜒 ∧ 𝜑) ∧ 𝜃) → 𝜓) | ||
Theorem | ad2antrl 760 | Deduction adding two conjuncts to antecedent. (Contributed by NM, 19-Oct-1999.) |
⊢ (𝜑 → 𝜓) ⇒ ⊢ ((𝜒 ∧ (𝜑 ∧ 𝜃)) → 𝜓) | ||
Theorem | ad2antll 761 | Deduction adding conjuncts to antecedent. (Contributed by NM, 19-Oct-1999.) |
⊢ (𝜑 → 𝜓) ⇒ ⊢ ((𝜒 ∧ (𝜃 ∧ 𝜑)) → 𝜓) | ||
Theorem | ad3antrrr 762 | Deduction adding three conjuncts to antecedent. (Contributed by NM, 28-Jul-2012.) |
⊢ (𝜑 → 𝜓) ⇒ ⊢ ((((𝜑 ∧ 𝜒) ∧ 𝜃) ∧ 𝜏) → 𝜓) | ||
Theorem | ad3antlr 763 | Deduction adding three conjuncts to antecedent. (Contributed by Mario Carneiro, 5-Jan-2017.) |
⊢ (𝜑 → 𝜓) ⇒ ⊢ ((((𝜒 ∧ 𝜑) ∧ 𝜃) ∧ 𝜏) → 𝜓) | ||
Theorem | ad4antr 764 | Deduction adding 4 conjuncts to antecedent. (Contributed by Mario Carneiro, 4-Jan-2017.) |
⊢ (𝜑 → 𝜓) ⇒ ⊢ (((((𝜑 ∧ 𝜒) ∧ 𝜃) ∧ 𝜏) ∧ 𝜂) → 𝜓) | ||
Theorem | ad4antlr 765 | Deduction adding 4 conjuncts to antecedent. (Contributed by Mario Carneiro, 5-Jan-2017.) |
⊢ (𝜑 → 𝜓) ⇒ ⊢ (((((𝜒 ∧ 𝜑) ∧ 𝜃) ∧ 𝜏) ∧ 𝜂) → 𝜓) | ||
Theorem | ad5antr 766 | Deduction adding 5 conjuncts to antecedent. (Contributed by Mario Carneiro, 4-Jan-2017.) |
⊢ (𝜑 → 𝜓) ⇒ ⊢ ((((((𝜑 ∧ 𝜒) ∧ 𝜃) ∧ 𝜏) ∧ 𝜂) ∧ 𝜁) → 𝜓) | ||
Theorem | ad5antlr 767 | Deduction adding 5 conjuncts to antecedent. (Contributed by Mario Carneiro, 5-Jan-2017.) |
⊢ (𝜑 → 𝜓) ⇒ ⊢ ((((((𝜒 ∧ 𝜑) ∧ 𝜃) ∧ 𝜏) ∧ 𝜂) ∧ 𝜁) → 𝜓) | ||
Theorem | ad6antr 768 | Deduction adding 6 conjuncts to antecedent. (Contributed by Mario Carneiro, 4-Jan-2017.) |
⊢ (𝜑 → 𝜓) ⇒ ⊢ (((((((𝜑 ∧ 𝜒) ∧ 𝜃) ∧ 𝜏) ∧ 𝜂) ∧ 𝜁) ∧ 𝜎) → 𝜓) | ||
Theorem | ad6antlr 769 | Deduction adding 6 conjuncts to antecedent. (Contributed by Mario Carneiro, 5-Jan-2017.) |
⊢ (𝜑 → 𝜓) ⇒ ⊢ (((((((𝜒 ∧ 𝜑) ∧ 𝜃) ∧ 𝜏) ∧ 𝜂) ∧ 𝜁) ∧ 𝜎) → 𝜓) | ||
Theorem | ad7antr 770 | Deduction adding 7 conjuncts to antecedent. (Contributed by Mario Carneiro, 4-Jan-2017.) |
⊢ (𝜑 → 𝜓) ⇒ ⊢ ((((((((𝜑 ∧ 𝜒) ∧ 𝜃) ∧ 𝜏) ∧ 𝜂) ∧ 𝜁) ∧ 𝜎) ∧ 𝜌) → 𝜓) | ||
Theorem | ad7antlr 771 | Deduction adding 7 conjuncts to antecedent. (Contributed by Mario Carneiro, 5-Jan-2017.) |
⊢ (𝜑 → 𝜓) ⇒ ⊢ ((((((((𝜒 ∧ 𝜑) ∧ 𝜃) ∧ 𝜏) ∧ 𝜂) ∧ 𝜁) ∧ 𝜎) ∧ 𝜌) → 𝜓) | ||
Theorem | ad8antr 772 | Deduction adding 8 conjuncts to antecedent. (Contributed by Mario Carneiro, 4-Jan-2017.) |
⊢ (𝜑 → 𝜓) ⇒ ⊢ (((((((((𝜑 ∧ 𝜒) ∧ 𝜃) ∧ 𝜏) ∧ 𝜂) ∧ 𝜁) ∧ 𝜎) ∧ 𝜌) ∧ 𝜇) → 𝜓) | ||
Theorem | ad8antlr 773 | Deduction adding 8 conjuncts to antecedent. (Contributed by Mario Carneiro, 5-Jan-2017.) |
⊢ (𝜑 → 𝜓) ⇒ ⊢ (((((((((𝜒 ∧ 𝜑) ∧ 𝜃) ∧ 𝜏) ∧ 𝜂) ∧ 𝜁) ∧ 𝜎) ∧ 𝜌) ∧ 𝜇) → 𝜓) | ||
Theorem | ad9antr 774 | Deduction adding 9 conjuncts to antecedent. (Contributed by Mario Carneiro, 4-Jan-2017.) |
⊢ (𝜑 → 𝜓) ⇒ ⊢ ((((((((((𝜑 ∧ 𝜒) ∧ 𝜃) ∧ 𝜏) ∧ 𝜂) ∧ 𝜁) ∧ 𝜎) ∧ 𝜌) ∧ 𝜇) ∧ 𝜆) → 𝜓) | ||
Theorem | ad9antlr 775 | Deduction adding 9 conjuncts to antecedent. (Contributed by Mario Carneiro, 5-Jan-2017.) |
⊢ (𝜑 → 𝜓) ⇒ ⊢ ((((((((((𝜒 ∧ 𝜑) ∧ 𝜃) ∧ 𝜏) ∧ 𝜂) ∧ 𝜁) ∧ 𝜎) ∧ 𝜌) ∧ 𝜇) ∧ 𝜆) → 𝜓) | ||
Theorem | ad10antr 776 | Deduction adding 10 conjuncts to antecedent. (Contributed by Mario Carneiro, 4-Jan-2017.) |
⊢ (𝜑 → 𝜓) ⇒ ⊢ (((((((((((𝜑 ∧ 𝜒) ∧ 𝜃) ∧ 𝜏) ∧ 𝜂) ∧ 𝜁) ∧ 𝜎) ∧ 𝜌) ∧ 𝜇) ∧ 𝜆) ∧ 𝜅) → 𝜓) | ||
Theorem | ad10antlr 777 | Deduction adding 10 conjuncts to antecedent. (Contributed by Mario Carneiro, 5-Jan-2017.) |
⊢ (𝜑 → 𝜓) ⇒ ⊢ (((((((((((𝜒 ∧ 𝜑) ∧ 𝜃) ∧ 𝜏) ∧ 𝜂) ∧ 𝜁) ∧ 𝜎) ∧ 𝜌) ∧ 𝜇) ∧ 𝜆) ∧ 𝜅) → 𝜓) | ||
Theorem | ad2ant2l 778 | Deduction adding two conjuncts to antecedent. (Contributed by NM, 8-Jan-2006.) |
⊢ ((𝜑 ∧ 𝜓) → 𝜒) ⇒ ⊢ (((𝜃 ∧ 𝜑) ∧ (𝜏 ∧ 𝜓)) → 𝜒) | ||
Theorem | ad2ant2r 779 | Deduction adding two conjuncts to antecedent. (Contributed by NM, 8-Jan-2006.) |
⊢ ((𝜑 ∧ 𝜓) → 𝜒) ⇒ ⊢ (((𝜑 ∧ 𝜃) ∧ (𝜓 ∧ 𝜏)) → 𝜒) | ||
Theorem | ad2ant2lr 780 | Deduction adding two conjuncts to antecedent. (Contributed by NM, 23-Nov-2007.) |
⊢ ((𝜑 ∧ 𝜓) → 𝜒) ⇒ ⊢ (((𝜃 ∧ 𝜑) ∧ (𝜓 ∧ 𝜏)) → 𝜒) | ||
Theorem | ad2ant2rl 781 | Deduction adding two conjuncts to antecedent. (Contributed by NM, 24-Nov-2007.) |
⊢ ((𝜑 ∧ 𝜓) → 𝜒) ⇒ ⊢ (((𝜑 ∧ 𝜃) ∧ (𝜏 ∧ 𝜓)) → 𝜒) | ||
Theorem | adantl3r 782 | Deduction adding 1 conjunct to antecedent. (Contributed by Thierry Arnoux, 11-Feb-2018.) |
⊢ ((((𝜑 ∧ 𝜌) ∧ 𝜇) ∧ 𝜆) → 𝜅) ⇒ ⊢ (((((𝜑 ∧ 𝜎) ∧ 𝜌) ∧ 𝜇) ∧ 𝜆) → 𝜅) | ||
Theorem | adantl4r 783 | Deduction adding 1 conjunct to antecedent. (Contributed by Thierry Arnoux, 11-Feb-2018.) |
⊢ (((((𝜑 ∧ 𝜎) ∧ 𝜌) ∧ 𝜇) ∧ 𝜆) → 𝜅) ⇒ ⊢ ((((((𝜑 ∧ 𝜁) ∧ 𝜎) ∧ 𝜌) ∧ 𝜇) ∧ 𝜆) → 𝜅) | ||
Theorem | adantl5r 784 | Deduction adding 1 conjunct to antecedent. (Contributed by Thierry Arnoux, 11-Feb-2018.) |
⊢ ((((((𝜑 ∧ 𝜁) ∧ 𝜎) ∧ 𝜌) ∧ 𝜇) ∧ 𝜆) → 𝜅) ⇒ ⊢ (((((((𝜑 ∧ 𝜂) ∧ 𝜁) ∧ 𝜎) ∧ 𝜌) ∧ 𝜇) ∧ 𝜆) → 𝜅) | ||
Theorem | adantl6r 785 | Deduction adding 1 conjunct to antecedent. (Contributed by Thierry Arnoux, 11-Feb-2018.) |
⊢ (((((((𝜑 ∧ 𝜂) ∧ 𝜁) ∧ 𝜎) ∧ 𝜌) ∧ 𝜇) ∧ 𝜆) → 𝜅) ⇒ ⊢ ((((((((𝜑 ∧ 𝜏) ∧ 𝜂) ∧ 𝜁) ∧ 𝜎) ∧ 𝜌) ∧ 𝜇) ∧ 𝜆) → 𝜅) | ||
Theorem | simpll 786 | Simplification of a conjunction. (Contributed by NM, 18-Mar-2007.) |
⊢ (((𝜑 ∧ 𝜓) ∧ 𝜒) → 𝜑) | ||
Theorem | simplld 787 | Deduction form of simpll 786, eliminating a double conjunct. (Contributed by Glauco Siliprandi, 11-Dec-2019.) |
⊢ (𝜑 → ((𝜓 ∧ 𝜒) ∧ 𝜃)) ⇒ ⊢ (𝜑 → 𝜓) | ||
Theorem | simplr 788 | Simplification of a conjunction. (Contributed by NM, 20-Mar-2007.) |
⊢ (((𝜑 ∧ 𝜓) ∧ 𝜒) → 𝜓) | ||
Theorem | simplrd 789 | Deduction eliminating a double conjunct. (Contributed by Glauco Siliprandi, 11-Dec-2019.) |
⊢ (𝜑 → ((𝜓 ∧ 𝜒) ∧ 𝜃)) ⇒ ⊢ (𝜑 → 𝜒) | ||
Theorem | simprl 790 | Simplification of a conjunction. (Contributed by NM, 21-Mar-2007.) |
⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒)) → 𝜓) | ||
Theorem | simprld 791 | Deduction eliminating a double conjunct. (Contributed by Glauco Siliprandi, 11-Dec-2019.) |
⊢ (𝜑 → (𝜓 ∧ (𝜒 ∧ 𝜃))) ⇒ ⊢ (𝜑 → 𝜒) | ||
Theorem | simprr 792 | Simplification of a conjunction. (Contributed by NM, 21-Mar-2007.) |
⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒)) → 𝜒) | ||
Theorem | simprrd 793 | Deduction form of simprr 792, eliminating a double conjunct. (Contributed by Glauco Siliprandi, 11-Dec-2019.) |
⊢ (𝜑 → (𝜓 ∧ (𝜒 ∧ 𝜃))) ⇒ ⊢ (𝜑 → 𝜃) | ||
Theorem | simplll 794 | Simplification of a conjunction. (Contributed by Jeff Hankins, 28-Jul-2009.) |
⊢ ((((𝜑 ∧ 𝜓) ∧ 𝜒) ∧ 𝜃) → 𝜑) | ||
Theorem | simpllr 795 | Simplification of a conjunction. (Contributed by Jeff Hankins, 28-Jul-2009.) |
⊢ ((((𝜑 ∧ 𝜓) ∧ 𝜒) ∧ 𝜃) → 𝜓) | ||
Theorem | simplrl 796 | Simplification of a conjunction. (Contributed by Jeff Hankins, 28-Jul-2009.) |
⊢ (((𝜑 ∧ (𝜓 ∧ 𝜒)) ∧ 𝜃) → 𝜓) | ||
Theorem | simplrr 797 | Simplification of a conjunction. (Contributed by Jeff Hankins, 28-Jul-2009.) |
⊢ (((𝜑 ∧ (𝜓 ∧ 𝜒)) ∧ 𝜃) → 𝜒) | ||
Theorem | simprll 798 | Simplification of a conjunction. (Contributed by Jeff Hankins, 28-Jul-2009.) |
⊢ ((𝜑 ∧ ((𝜓 ∧ 𝜒) ∧ 𝜃)) → 𝜓) | ||
Theorem | simprlr 799 | Simplification of a conjunction. (Contributed by Jeff Hankins, 28-Jul-2009.) |
⊢ ((𝜑 ∧ ((𝜓 ∧ 𝜒) ∧ 𝜃)) → 𝜒) | ||
Theorem | simprrl 800 | Simplification of a conjunction. (Contributed by Jeff Hankins, 28-Jul-2009.) |
⊢ ((𝜑 ∧ (𝜓 ∧ (𝜒 ∧ 𝜃))) → 𝜒) |
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