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Theorem List for Metamath Proof Explorer - 10001-10100   *Has distinct variable group(s)
TypeLabelDescription
Statement

Theoremlttri4 10001 Trichotomy law for 'less than'. (Contributed by NM, 20-Sep-2007.) (Proof shortened by Andrew Salmon, 19-Nov-2011.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ) → (𝐴 < 𝐵𝐴 = 𝐵𝐵 < 𝐴))

Theoremletri3 10002 Trichotomy law. (Contributed by NM, 14-May-1999.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ) → (𝐴 = 𝐵 ↔ (𝐴𝐵𝐵𝐴)))

Theoremleloe 10003 'Less than or equal to' expressed in terms of 'less than' or 'equals'. (Contributed by NM, 13-May-1999.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ) → (𝐴𝐵 ↔ (𝐴 < 𝐵𝐴 = 𝐵)))

Theoremeqlelt 10004 Equality in terms of 'less than or equal to', 'less than'. (Contributed by NM, 7-Apr-2001.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ) → (𝐴 = 𝐵 ↔ (𝐴𝐵 ∧ ¬ 𝐴 < 𝐵)))

Theoremltle 10005 'Less than' implies 'less than or equal to'. (Contributed by NM, 25-Aug-1999.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ) → (𝐴 < 𝐵𝐴𝐵))

Theoremleltne 10006 'Less than or equal to' implies 'less than' is not 'equals'. (Contributed by NM, 27-Jul-1999.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ∧ 𝐴𝐵) → (𝐴 < 𝐵𝐵𝐴))

Theoremlelttr 10007 Transitive law. (Contributed by NM, 23-May-1999.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ∧ 𝐶 ∈ ℝ) → ((𝐴𝐵𝐵 < 𝐶) → 𝐴 < 𝐶))

Theoremltletr 10008 Transitive law. (Contributed by NM, 25-Aug-1999.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ∧ 𝐶 ∈ ℝ) → ((𝐴 < 𝐵𝐵𝐶) → 𝐴 < 𝐶))

Theoremltleletr 10009 Transitive law, weaker form of ltletr 10008. (Contributed by AV, 14-Oct-2018.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ∧ 𝐶 ∈ ℝ) → ((𝐴 < 𝐵𝐵𝐶) → 𝐴𝐶))

Theoremletr 10010 Transitive law. (Contributed by NM, 12-Nov-1999.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ∧ 𝐶 ∈ ℝ) → ((𝐴𝐵𝐵𝐶) → 𝐴𝐶))

Theoremltnr 10011 'Less than' is irreflexive. (Contributed by NM, 18-Aug-1999.)
(𝐴 ∈ ℝ → ¬ 𝐴 < 𝐴)

Theoremleid 10012 'Less than or equal to' is reflexive. (Contributed by NM, 18-Aug-1999.)
(𝐴 ∈ ℝ → 𝐴𝐴)

Theoremltne 10013 'Less than' implies not equal. (Contributed by NM, 9-Oct-1999.) (Revised by Mario Carneiro, 16-Sep-2015.)
((𝐴 ∈ ℝ ∧ 𝐴 < 𝐵) → 𝐵𝐴)

Theoremltnsym 10014 'Less than' is not symmetric. (Contributed by NM, 8-Jan-2002.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ) → (𝐴 < 𝐵 → ¬ 𝐵 < 𝐴))

Theoremltnsym2 10015 'Less than' is antisymmetric and irreflexive. (Contributed by NM, 13-Aug-2005.) (Proof shortened by Andrew Salmon, 19-Nov-2011.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ) → ¬ (𝐴 < 𝐵𝐵 < 𝐴))

Theoremletric 10016 Trichotomy law. (Contributed by NM, 18-Aug-1999.) (Proof shortened by Andrew Salmon, 19-Nov-2011.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ) → (𝐴𝐵𝐵𝐴))

Theoremltlen 10017 'Less than' expressed in terms of 'less than or equal to'. (Contributed by NM, 27-Oct-1999.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ) → (𝐴 < 𝐵 ↔ (𝐴𝐵𝐵𝐴)))

Theoremeqle 10018 Equality implies 'less than or equal to'. (Contributed by NM, 4-Apr-2005.)
((𝐴 ∈ ℝ ∧ 𝐴 = 𝐵) → 𝐴𝐵)

Theoremeqled 10019 Equality implies 'less than or equal to'. (Contributed by Glauco Siliprandi, 11-Dec-2019.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐴 = 𝐵)       (𝜑𝐴𝐵)

Theoremltadd2 10020 Addition to both sides of 'less than'. (Contributed by NM, 12-Nov-1999.) (Revised by Mario Carneiro, 27-May-2016.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ∧ 𝐶 ∈ ℝ) → (𝐴 < 𝐵 ↔ (𝐶 + 𝐴) < (𝐶 + 𝐵)))

Theoremne0gt0 10021 A nonzero nonnegative number is positive. (Contributed by NM, 20-Nov-2007.)
((𝐴 ∈ ℝ ∧ 0 ≤ 𝐴) → (𝐴 ≠ 0 ↔ 0 < 𝐴))

Theoremlecasei 10022 Ordering elimination by cases. (Contributed by NM, 6-Jul-2007.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)    &   ((𝜑𝐴𝐵) → 𝜓)    &   ((𝜑𝐵𝐴) → 𝜓)       (𝜑𝜓)

Theoremlelttric 10023 Trichotomy law. (Contributed by NM, 4-Apr-2005.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ) → (𝐴𝐵𝐵 < 𝐴))

Theoremltlecasei 10024 Ordering elimination by cases. (Contributed by NM, 1-Jul-2007.) (Proof shortened by Mario Carneiro, 27-May-2016.)
((𝜑𝐴 < 𝐵) → 𝜓)    &   ((𝜑𝐵𝐴) → 𝜓)    &   (𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)       (𝜑𝜓)

Theoremltnri 10025 'Less than' is irreflexive. (Contributed by NM, 18-Aug-1999.)
𝐴 ∈ ℝ        ¬ 𝐴 < 𝐴

Theoremeqlei 10026 Equality implies 'less than or equal to'. (Contributed by NM, 23-May-1999.) (Revised by Alexander van der Vekens, 20-Mar-2018.)
𝐴 ∈ ℝ       (𝐴 = 𝐵𝐴𝐵)

Theoremeqlei2 10027 Equality implies 'less than or equal to'. (Contributed by Alexander van der Vekens, 20-Mar-2018.)
𝐴 ∈ ℝ       (𝐵 = 𝐴𝐵𝐴)

Theoremgtneii 10028 'Less than' implies not equal. (Contributed by Mario Carneiro, 30-Sep-2013.)
𝐴 ∈ ℝ    &   𝐴 < 𝐵       𝐵𝐴

Theoremltneii 10029 'Greater than' implies not equal. (Contributed by Mario Carneiro, 16-Sep-2015.)
𝐴 ∈ ℝ    &   𝐴 < 𝐵       𝐴𝐵

Theoremlttri2i 10030 Consequence of trichotomy. (Contributed by NM, 19-Jan-1997.)
𝐴 ∈ ℝ    &   𝐵 ∈ ℝ       (𝐴𝐵 ↔ (𝐴 < 𝐵𝐵 < 𝐴))

Theoremlttri3i 10031 Consequence of trichotomy. (Contributed by NM, 14-May-1999.)
𝐴 ∈ ℝ    &   𝐵 ∈ ℝ       (𝐴 = 𝐵 ↔ (¬ 𝐴 < 𝐵 ∧ ¬ 𝐵 < 𝐴))

Theoremletri3i 10032 Consequence of trichotomy. (Contributed by NM, 14-May-1999.)
𝐴 ∈ ℝ    &   𝐵 ∈ ℝ       (𝐴 = 𝐵 ↔ (𝐴𝐵𝐵𝐴))

Theoremleloei 10033 'Less than or equal to' in terms of 'less than'. (Contributed by NM, 14-May-1999.)
𝐴 ∈ ℝ    &   𝐵 ∈ ℝ       (𝐴𝐵 ↔ (𝐴 < 𝐵𝐴 = 𝐵))

Theoremltleni 10034 'Less than' expressed in terms of 'less than or equal to'. (Contributed by NM, 27-Oct-1999.)
𝐴 ∈ ℝ    &   𝐵 ∈ ℝ       (𝐴 < 𝐵 ↔ (𝐴𝐵𝐵𝐴))

Theoremltnsymi 10035 'Less than' is not symmetric. (Contributed by NM, 6-May-1999.)
𝐴 ∈ ℝ    &   𝐵 ∈ ℝ       (𝐴 < 𝐵 → ¬ 𝐵 < 𝐴)

Theoremlenlti 10036 'Less than or equal to' in terms of 'less than'. (Contributed by NM, 24-May-1999.)
𝐴 ∈ ℝ    &   𝐵 ∈ ℝ       (𝐴𝐵 ↔ ¬ 𝐵 < 𝐴)

Theoremltnlei 10037 'Less than' in terms of 'less than or equal to'. (Contributed by NM, 11-Jul-2005.)
𝐴 ∈ ℝ    &   𝐵 ∈ ℝ       (𝐴 < 𝐵 ↔ ¬ 𝐵𝐴)

Theoremltlei 10038 'Less than' implies 'less than or equal to'. (Contributed by NM, 14-May-1999.)
𝐴 ∈ ℝ    &   𝐵 ∈ ℝ       (𝐴 < 𝐵𝐴𝐵)

Theoremltleii 10039 'Less than' implies 'less than or equal to' (inference). (Contributed by NM, 22-Aug-1999.)
𝐴 ∈ ℝ    &   𝐵 ∈ ℝ    &   𝐴 < 𝐵       𝐴𝐵

Theoremltnei 10040 'Less than' implies not equal. (Contributed by NM, 28-Jul-1999.)
𝐴 ∈ ℝ    &   𝐵 ∈ ℝ       (𝐴 < 𝐵𝐵𝐴)

Theoremletrii 10041 Trichotomy law for 'less than or equal to'. (Contributed by NM, 2-Aug-1999.)
𝐴 ∈ ℝ    &   𝐵 ∈ ℝ       (𝐴𝐵𝐵𝐴)

Theoremlttri 10042 'Less than' is transitive. Theorem I.17 of [Apostol] p. 20. (Contributed by NM, 14-May-1999.)
𝐴 ∈ ℝ    &   𝐵 ∈ ℝ    &   𝐶 ∈ ℝ       ((𝐴 < 𝐵𝐵 < 𝐶) → 𝐴 < 𝐶)

Theoremlelttri 10043 'Less than or equal to', 'less than' transitive law. (Contributed by NM, 14-May-1999.)
𝐴 ∈ ℝ    &   𝐵 ∈ ℝ    &   𝐶 ∈ ℝ       ((𝐴𝐵𝐵 < 𝐶) → 𝐴 < 𝐶)

Theoremltletri 10044 'Less than', 'less than or equal to' transitive law. (Contributed by NM, 14-May-1999.)
𝐴 ∈ ℝ    &   𝐵 ∈ ℝ    &   𝐶 ∈ ℝ       ((𝐴 < 𝐵𝐵𝐶) → 𝐴 < 𝐶)

Theoremletri 10045 'Less than or equal to' is transitive. (Contributed by NM, 14-May-1999.)
𝐴 ∈ ℝ    &   𝐵 ∈ ℝ    &   𝐶 ∈ ℝ       ((𝐴𝐵𝐵𝐶) → 𝐴𝐶)

Theoremle2tri3i 10046 Extended trichotomy law for 'less than or equal to'. (Contributed by NM, 14-Aug-2000.)
𝐴 ∈ ℝ    &   𝐵 ∈ ℝ    &   𝐶 ∈ ℝ       ((𝐴𝐵𝐵𝐶𝐶𝐴) ↔ (𝐴 = 𝐵𝐵 = 𝐶𝐶 = 𝐴))

Theoremltadd2i 10047 Addition to both sides of 'less than'. (Contributed by NM, 21-Jan-1997.) (Proof shortened by OpenAI, 25-Mar-2020.)
𝐴 ∈ ℝ    &   𝐵 ∈ ℝ    &   𝐶 ∈ ℝ       (𝐴 < 𝐵 ↔ (𝐶 + 𝐴) < (𝐶 + 𝐵))

Theoremmulgt0i 10048 The product of two positive numbers is positive. (Contributed by NM, 16-May-1999.)
𝐴 ∈ ℝ    &   𝐵 ∈ ℝ       ((0 < 𝐴 ∧ 0 < 𝐵) → 0 < (𝐴 · 𝐵))

Theoremmulgt0ii 10049 The product of two positive numbers is positive. (Contributed by NM, 18-May-1999.)
𝐴 ∈ ℝ    &   𝐵 ∈ ℝ    &   0 < 𝐴    &   0 < 𝐵       0 < (𝐴 · 𝐵)

Theoremltnrd 10050 'Less than' is irreflexive. (Contributed by Mario Carneiro, 27-May-2016.)
(𝜑𝐴 ∈ ℝ)       (𝜑 → ¬ 𝐴 < 𝐴)

Theoremgtned 10051 'Less than' implies not equal. (Contributed by Mario Carneiro, 27-May-2016.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐴 < 𝐵)       (𝜑𝐵𝐴)

Theoremltned 10052 'Greater than' implies not equal. (Contributed by Mario Carneiro, 27-May-2016.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐴 < 𝐵)       (𝜑𝐴𝐵)

Theoremne0gt0d 10053 A nonzero nonnegative number is positive. (Contributed by Mario Carneiro, 27-May-2016.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑 → 0 ≤ 𝐴)    &   (𝜑𝐴 ≠ 0)       (𝜑 → 0 < 𝐴)

Theoremlttrid 10054 Ordering on reals satisfies strict trichotomy. (Contributed by Mario Carneiro, 27-May-2016.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)       (𝜑 → (𝐴 < 𝐵 ↔ ¬ (𝐴 = 𝐵𝐵 < 𝐴)))

Theoremlttri2d 10055 Consequence of trichotomy. (Contributed by Mario Carneiro, 27-May-2016.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)       (𝜑 → (𝐴𝐵 ↔ (𝐴 < 𝐵𝐵 < 𝐴)))

Theoremlttri3d 10056 Consequence of trichotomy. (Contributed by Mario Carneiro, 27-May-2016.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)       (𝜑 → (𝐴 = 𝐵 ↔ (¬ 𝐴 < 𝐵 ∧ ¬ 𝐵 < 𝐴)))

Theoremlttri4d 10057 Trichotomy law for 'less than'. (Contributed by NM, 20-Sep-2007.) (Proof shortened by Andrew Salmon, 19-Nov-2011.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)       (𝜑 → (𝐴 < 𝐵𝐴 = 𝐵𝐵 < 𝐴))

Theoremletri3d 10058 Consequence of trichotomy. (Contributed by Mario Carneiro, 27-May-2016.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)       (𝜑 → (𝐴 = 𝐵 ↔ (𝐴𝐵𝐵𝐴)))

Theoremleloed 10059 'Less than or equal to' in terms of 'less than'. (Contributed by Mario Carneiro, 27-May-2016.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)       (𝜑 → (𝐴𝐵 ↔ (𝐴 < 𝐵𝐴 = 𝐵)))

Theoremeqleltd 10060 Equality in terms of 'less than or equal to', 'less than'. (Contributed by NM, 7-Apr-2001.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)       (𝜑 → (𝐴 = 𝐵 ↔ (𝐴𝐵 ∧ ¬ 𝐴 < 𝐵)))

Theoremltlend 10061 'Less than' expressed in terms of 'less than or equal to'. (Contributed by Mario Carneiro, 27-May-2016.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)       (𝜑 → (𝐴 < 𝐵 ↔ (𝐴𝐵𝐵𝐴)))

Theoremlenltd 10062 'Less than or equal to' in terms of 'less than'. (Contributed by Mario Carneiro, 27-May-2016.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)       (𝜑 → (𝐴𝐵 ↔ ¬ 𝐵 < 𝐴))

Theoremltnled 10063 'Less than' in terms of 'less than or equal to'. (Contributed by Mario Carneiro, 27-May-2016.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)       (𝜑 → (𝐴 < 𝐵 ↔ ¬ 𝐵𝐴))

Theoremltled 10064 'Less than' implies 'less than or equal to'. (Contributed by Mario Carneiro, 27-May-2016.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)    &   (𝜑𝐴 < 𝐵)       (𝜑𝐴𝐵)

Theoremltnsymd 10065 'Less than' implies 'less than or equal to'. (Contributed by Mario Carneiro, 27-May-2016.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)    &   (𝜑𝐴 < 𝐵)       (𝜑 → ¬ 𝐵 < 𝐴)

Theoremnltled 10066 'Not less than ' implies 'less than or equal to'. (Contributed by Glauco Siliprandi, 11-Dec-2019.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)    &   (𝜑 → ¬ 𝐵 < 𝐴)       (𝜑𝐴𝐵)

Theoremlensymd 10067 'Less than or equal to' implies 'not less than'. (Contributed by Glauco Siliprandi, 11-Dec-2019.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)    &   (𝜑𝐴𝐵)       (𝜑 → ¬ 𝐵 < 𝐴)

Theoremletrid 10068 Trichotomy law for 'less than or equal to'. (Contributed by Mario Carneiro, 27-May-2016.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)       (𝜑 → (𝐴𝐵𝐵𝐴))

Theoremleltned 10069 'Less than or equal to' implies 'less than' is not 'equals'. (Contributed by Mario Carneiro, 27-May-2016.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)    &   (𝜑𝐴𝐵)       (𝜑 → (𝐴 < 𝐵𝐵𝐴))

Theoremleneltd 10070 'Less than or equal to' and 'not equals' implies 'less than'. (Contributed by Glauco Siliprandi, 11-Dec-2019.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)    &   (𝜑𝐴𝐵)    &   (𝜑𝐵𝐴)       (𝜑𝐴 < 𝐵)

Theoremmulgt0d 10071 The product of two positive numbers is positive. (Contributed by Mario Carneiro, 27-May-2016.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)    &   (𝜑 → 0 < 𝐴)    &   (𝜑 → 0 < 𝐵)       (𝜑 → 0 < (𝐴 · 𝐵))

Theoremltadd2d 10072 Addition to both sides of 'less than'. (Contributed by Mario Carneiro, 27-May-2016.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)    &   (𝜑𝐶 ∈ ℝ)       (𝜑 → (𝐴 < 𝐵 ↔ (𝐶 + 𝐴) < (𝐶 + 𝐵)))

Theoremletrd 10073 Transitive law deduction for 'less than or equal to'. (Contributed by NM, 20-May-2005.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)    &   (𝜑𝐶 ∈ ℝ)    &   (𝜑𝐴𝐵)    &   (𝜑𝐵𝐶)       (𝜑𝐴𝐶)

Theoremlelttrd 10074 Transitive law deduction for 'less than or equal to', 'less than'. (Contributed by NM, 8-Jan-2006.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)    &   (𝜑𝐶 ∈ ℝ)    &   (𝜑𝐴𝐵)    &   (𝜑𝐵 < 𝐶)       (𝜑𝐴 < 𝐶)

Theoremltadd2dd 10075 Addition to both sides of 'less than'. (Contributed by Mario Carneiro, 30-May-2016.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)    &   (𝜑𝐶 ∈ ℝ)    &   (𝜑𝐴 < 𝐵)       (𝜑 → (𝐶 + 𝐴) < (𝐶 + 𝐵))

Theoremltletrd 10076 Transitive law deduction for 'less than', 'less than or equal to'. (Contributed by NM, 9-Jan-2006.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)    &   (𝜑𝐶 ∈ ℝ)    &   (𝜑𝐴 < 𝐵)    &   (𝜑𝐵𝐶)       (𝜑𝐴 < 𝐶)

Theoremlttrd 10077 Transitive law deduction for 'less than'. (Contributed by NM, 9-Jan-2006.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)    &   (𝜑𝐶 ∈ ℝ)    &   (𝜑𝐴 < 𝐵)    &   (𝜑𝐵 < 𝐶)       (𝜑𝐴 < 𝐶)

Theoremlelttrdi 10078 If a number is less than another number, and the other number is less than or equal to a third number, the first number is less than the third number. (Contributed by Alexander van der Vekens, 24-Mar-2018.)
(𝜑 → (𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ∧ 𝐶 ∈ ℝ))    &   (𝜑𝐵𝐶)       (𝜑 → (𝐴 < 𝐵𝐴 < 𝐶))

Theoremdedekind 10079* The Dedekind cut theorem. This theorem, which may be used to replace ax-pre-sup 9893 with appropriate adjustments, states that, if 𝐴 completely preceeds 𝐵, then there is some number separating the two of them. (Contributed by Scott Fenton, 13-Jun-2013.)
((𝐴 ⊆ ℝ ∧ 𝐵 ⊆ ℝ ∧ ∀𝑥𝐴𝑦𝐵 𝑥 < 𝑦) → ∃𝑧 ∈ ℝ ∀𝑥𝐴𝑦𝐵 (𝑥𝑧𝑧𝑦))

Theoremdedekindle 10080* The Dedekind cut theorem, with the hypothesis weakened to only require non-strict less than. (Contributed by Scott Fenton, 2-Jul-2013.)
((𝐴 ⊆ ℝ ∧ 𝐵 ⊆ ℝ ∧ ∀𝑥𝐴𝑦𝐵 𝑥𝑦) → ∃𝑧 ∈ ℝ ∀𝑥𝐴𝑦𝐵 (𝑥𝑧𝑧𝑦))

5.2.5  Initial properties of the complex numbers

Theoremmul12 10081 Commutative/associative law for multiplication. (Contributed by NM, 30-Apr-2005.)
((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ ∧ 𝐶 ∈ ℂ) → (𝐴 · (𝐵 · 𝐶)) = (𝐵 · (𝐴 · 𝐶)))

Theoremmul32 10082 Commutative/associative law. (Contributed by NM, 8-Oct-1999.)
((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ ∧ 𝐶 ∈ ℂ) → ((𝐴 · 𝐵) · 𝐶) = ((𝐴 · 𝐶) · 𝐵))

Theoremmul31 10083 Commutative/associative law. (Contributed by Scott Fenton, 3-Jan-2013.)
((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ ∧ 𝐶 ∈ ℂ) → ((𝐴 · 𝐵) · 𝐶) = ((𝐶 · 𝐵) · 𝐴))

Theoremmul4 10084 Rearrangement of 4 factors. (Contributed by NM, 8-Oct-1999.)
(((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) ∧ (𝐶 ∈ ℂ ∧ 𝐷 ∈ ℂ)) → ((𝐴 · 𝐵) · (𝐶 · 𝐷)) = ((𝐴 · 𝐶) · (𝐵 · 𝐷)))

Theoremmuladd11 10085 A simple product of sums expansion. (Contributed by NM, 21-Feb-2005.)
((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ) → ((1 + 𝐴) · (1 + 𝐵)) = ((1 + 𝐴) + (𝐵 + (𝐴 · 𝐵))))

Theorem1p1times 10086 Two times a number. (Contributed by NM, 18-May-1999.) (Revised by Mario Carneiro, 27-May-2016.)
(𝐴 ∈ ℂ → ((1 + 1) · 𝐴) = (𝐴 + 𝐴))

Theorempeano2cn 10087 A theorem for complex numbers analogous the second Peano postulate peano2nn 10909. (Contributed by NM, 17-Aug-2005.)
(𝐴 ∈ ℂ → (𝐴 + 1) ∈ ℂ)

Theorempeano2re 10088 A theorem for reals analogous the second Peano postulate peano2nn 10909. (Contributed by NM, 5-Jul-2005.)
(𝐴 ∈ ℝ → (𝐴 + 1) ∈ ℝ)

Theoremreaddcan 10089 Cancellation law for addition over the reals. (Contributed by Scott Fenton, 3-Jan-2013.) (Proof shortened by Mario Carneiro, 27-May-2016.)
((𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ∧ 𝐶 ∈ ℝ) → ((𝐶 + 𝐴) = (𝐶 + 𝐵) ↔ 𝐴 = 𝐵))

Theorem00id 10090 0 is its own additive identity. (Contributed by Scott Fenton, 3-Jan-2013.)
(0 + 0) = 0

Theoremmul02lem1 10091 Lemma for mul02 10093. If any real does not produce 0 when multiplied by 0, then any complex is equal to double itself. (Contributed by Scott Fenton, 3-Jan-2013.)
(((𝐴 ∈ ℝ ∧ (0 · 𝐴) ≠ 0) ∧ 𝐵 ∈ ℂ) → 𝐵 = (𝐵 + 𝐵))

Theoremmul02lem2 10092 Lemma for mul02 10093. Zero times a real is zero. (Contributed by Scott Fenton, 3-Jan-2013.)
(𝐴 ∈ ℝ → (0 · 𝐴) = 0)

Theoremmul02 10093 Multiplication by 0. Theorem I.6 of [Apostol] p. 18. Based on ideas by Eric Schmidt. (Contributed by NM, 10-Aug-1999.) (Revised by Scott Fenton, 3-Jan-2013.)
(𝐴 ∈ ℂ → (0 · 𝐴) = 0)

Theoremmul01 10094 Multiplication by 0. Theorem I.6 of [Apostol] p. 18. (Contributed by NM, 15-May-1999.) (Revised by Scott Fenton, 3-Jan-2013.)
(𝐴 ∈ ℂ → (𝐴 · 0) = 0)

Theoremaddid1 10095 0 is an additive identity. This used to be one of our complex number axioms, until it was found to be dependent on the others. Based on ideas by Eric Schmidt. (Contributed by Scott Fenton, 3-Jan-2013.) (Proof shortened by Mario Carneiro, 27-May-2016.)
(𝐴 ∈ ℂ → (𝐴 + 0) = 𝐴)

Theoremcnegex 10096* Existence of the negative of a complex number. (Contributed by Eric Schmidt, 21-May-2007.) (Revised by Scott Fenton, 3-Jan-2013.) (Proof shortened by Mario Carneiro, 27-May-2016.)
(𝐴 ∈ ℂ → ∃𝑥 ∈ ℂ (𝐴 + 𝑥) = 0)

Theoremcnegex2 10097* Existence of a left inverse for addition. (Contributed by Scott Fenton, 3-Jan-2013.)
(𝐴 ∈ ℂ → ∃𝑥 ∈ ℂ (𝑥 + 𝐴) = 0)

Theoremaddid2 10098 0 is a left identity for addition. This used to be one of our complex number axioms, until it was discovered that it was dependent on the others. Based on ideas by Eric Schmidt. (Contributed by Scott Fenton, 3-Jan-2013.)
(𝐴 ∈ ℂ → (0 + 𝐴) = 𝐴)

Theoremaddcan 10099 Cancellation law for addition. Theorem I.1 of [Apostol] p. 18. (Contributed by NM, 22-Nov-1994.) (Proof shortened by Mario Carneiro, 27-May-2016.)
((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ ∧ 𝐶 ∈ ℂ) → ((𝐴 + 𝐵) = (𝐴 + 𝐶) ↔ 𝐵 = 𝐶))

Theoremaddcan2 10100 Cancellation law for addition. (Contributed by NM, 30-Jul-2004.) (Revised by Scott Fenton, 3-Jan-2013.)
((𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ ∧ 𝐶 ∈ ℂ) → ((𝐴 + 𝐶) = (𝐵 + 𝐶) ↔ 𝐴 = 𝐵))

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