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Mirrors > Home > MPE Home > Th. List > fneq2 | Structured version Visualization version GIF version |
Description: Equality theorem for function predicate with domain. (Contributed by NM, 1-Aug-1994.) |
Ref | Expression |
---|---|
fneq2 | ⊢ (𝐴 = 𝐵 → (𝐹 Fn 𝐴 ↔ 𝐹 Fn 𝐵)) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | eqeq2 2621 | . . 3 ⊢ (𝐴 = 𝐵 → (dom 𝐹 = 𝐴 ↔ dom 𝐹 = 𝐵)) | |
2 | 1 | anbi2d 736 | . 2 ⊢ (𝐴 = 𝐵 → ((Fun 𝐹 ∧ dom 𝐹 = 𝐴) ↔ (Fun 𝐹 ∧ dom 𝐹 = 𝐵))) |
3 | df-fn 5807 | . 2 ⊢ (𝐹 Fn 𝐴 ↔ (Fun 𝐹 ∧ dom 𝐹 = 𝐴)) | |
4 | df-fn 5807 | . 2 ⊢ (𝐹 Fn 𝐵 ↔ (Fun 𝐹 ∧ dom 𝐹 = 𝐵)) | |
5 | 2, 3, 4 | 3bitr4g 302 | 1 ⊢ (𝐴 = 𝐵 → (𝐹 Fn 𝐴 ↔ 𝐹 Fn 𝐵)) |
Colors of variables: wff setvar class |
Syntax hints: → wi 4 ↔ wb 195 ∧ wa 383 = wceq 1475 dom cdm 5038 Fun wfun 5798 Fn wfn 5799 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1713 ax-4 1728 ax-ext 2590 |
This theorem depends on definitions: df-bi 196 df-an 385 df-cleq 2603 df-fn 5807 |
This theorem is referenced by: fneq2d 5896 fneq2i 5900 feq2 5940 foeq2 6025 f1o00 6083 eqfnfv2 6220 wfrlem1 7301 wfrlem15 7316 tfrlem12 7372 ixpeq1 7805 ac5 9182 0fz1 12232 esumcvgsum 29477 bnj90 30042 bnj919 30091 bnj535 30214 bnj1463 30377 frrlem1 31024 fnchoice 38211 |
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