Theorem consym1 31589

Description: A symmetry with ∧.

See negsym1 31586 for more information. (Contributed by Anthony Hart, 4-Sep-2011.)

Assertion

Ref	Expression
consym1	⊢ ((𝜓 ∧ (𝜓 ∧ ⊥)) → (𝜓 ∧ 𝜑))

Proof of Theorem consym1

Step	Hyp	Ref	Expression
1		falim 1489	. . 3 ⊢ (⊥ → ((𝜓 ∧ (𝜓 ∧ ⊥)) → (𝜓 ∧ 𝜑)))
2	1	ad2antll 761	. 2 ⊢ ((𝜓 ∧ (𝜓 ∧ ⊥)) → ((𝜓 ∧ (𝜓 ∧ ⊥)) → (𝜓 ∧ 𝜑)))
3	2	pm2.43i 50	1 ⊢ ((𝜓 ∧ (𝜓 ∧ ⊥)) → (𝜓 ∧ 𝜑))

Syntax hints:   → wi 4   ∧ wa 383  ⊥wfal 1480

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8

This theorem depends on definitions:  df-bi 196  df-an 385  df-tru 1478  df-fal 1481

This theorem is referenced by: (None)