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Theorem sb6 1644
Description: Equivalence for substitution. Compare Theorem 6.2 of [Quine] p. 40. Also proved as Lemmas 16 and 17 of [Tarski] p. 70.
Assertion
Ref Expression
sb6 |- ([y / x]ph <-> A.x(x = y -> ph))
Distinct variable group:   x,y

Proof of Theorem sb6
StepHypRef Expression
1 sb56 1643 . . 3 |- (E.x(x = y /\ ph) <-> A.x(x = y -> ph))
21anbi2i 538 . 2 |- (((x = y -> ph) /\ E.x(x = y /\ ph)) <-> ((x = y -> ph) /\ A.x(x = y -> ph)))
3 df-sb 1536 . 2 |- ([y / x]ph <-> ((x = y -> ph) /\ E.x(x = y /\ ph)))
4 ax-4 1319 . . 3 |- (A.x(x = y -> ph) -> (x = y -> ph))
54pm4.71ri 700 . 2 |- (A.x(x = y -> ph) <-> ((x = y -> ph) /\ A.x(x = y -> ph)))
62, 3, 53bitr4i 200 1 |- ([y / x]ph <-> A.x(x = y -> ph))
Colors of variables: wff set class
Syntax hints:   -> wi 3   <-> wb 163   /\ wa 240  A.wal 1296   = wceq 1298  E.wex 1326  [wsbc 1534
This theorem is referenced by:  sb5 1645  2sb6 1726  sb6a 1727  exsb 1741  sbal2 1749
This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-gen 1305  ax-4 1319  ax-5o 1321  ax-6o 1324  ax-9o 1481  ax-16 1580  ax-11o 1588
This theorem depends on definitions:  df-bi 164  df-an 242  df-ex 1327  df-sb 1536
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