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Theorem sb5 1645
Description: Equivalence for substitution. Similar to Theorem 6.1 of [Quine] p. 40.
Assertion
Ref Expression
sb5 |- ([y / x]ph <-> E.x(x = y /\ ph))
Distinct variable group:   x,y

Proof of Theorem sb5
StepHypRef Expression
1 sb6 1644 . 2 |- ([y / x]ph <-> A.x(x = y -> ph))
2 sb56 1643 . 2 |- (E.x(x = y /\ ph) <-> A.x(x = y -> ph))
31, 2bitr4i 193 1 |- ([y / x]ph <-> E.x(x = y /\ ph))
Colors of variables: wff set class
Syntax hints:   -> wi 3   <-> wb 163   /\ wa 240  A.wal 1296   = wceq 1298  E.wex 1326  [wsbc 1534
This theorem is referenced by:  2sb5 1725  dfsb7 1730  sb7f 1731  sbelx 1735  sbc5g 2470  pm14.122b 16387
This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-gen 1305  ax-4 1319  ax-5o 1321  ax-6o 1324  ax-9o 1481  ax-16 1580  ax-11o 1588
This theorem depends on definitions:  df-bi 164  df-an 242  df-ex 1327  df-sb 1536
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