Metamath Proof Explorer < Previous   Next > Nearby theorems Mirrors  >  Home  >  MPE Home  >  Th. List  >  resdmdfsn Structured version   Unicode version

Theorem resdmdfsn 5167
 Description: Restricting a function to a domain without one element of the domain of the function, and adding a pair of this element and the function value of the element results in the function itself. (Contributed by AV, 2-Dec-2018.)
Assertion
Ref Expression
resdmdfsn

Proof of Theorem resdmdfsn
StepHypRef Expression
1 resindm 5166 . 2
2 indif1 3718 . . . . 5
3 incom 3656 . . . . . . 7
4 inv1 3790 . . . . . . 7
53, 4eqtri 2452 . . . . . 6
65difeq1i 3580 . . . . 5
72, 6eqtri 2452 . . . 4
87a1i 11 . . 3
98reseq2d 5122 . 2
101, 9eqtr3d 2466 1
 Colors of variables: wff setvar class Syntax hints:   wi 4   wceq 1438  cvv 3082   cdif 3434   cin 3436  csn 3997   cdm 4851   cres 4853   wrel 4856 This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1666  ax-4 1679  ax-5 1749  ax-6 1795  ax-7 1840  ax-9 1873  ax-10 1888  ax-11 1893  ax-12 1906  ax-13 2054  ax-ext 2401  ax-sep 4544  ax-nul 4553  ax-pr 4658 This theorem depends on definitions:  df-bi 189  df-or 372  df-an 373  df-3an 985  df-tru 1441  df-ex 1661  df-nf 1665  df-sb 1788  df-clab 2409  df-cleq 2415  df-clel 2418  df-nfc 2573  df-ne 2621  df-ral 2781  df-rex 2782  df-rab 2785  df-v 3084  df-dif 3440  df-un 3442  df-in 3444  df-ss 3451  df-nul 3763  df-if 3911  df-sn 3998  df-pr 4000  df-op 4004  df-br 4422  df-opab 4481  df-xp 4857  df-rel 4858  df-dm 4861  df-res 4863 This theorem is referenced by:  funresdfunsn  6119
 Copyright terms: Public domain W3C validator