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Statement List for Metamath Proof Explorer - 6801-6900 - Page 69 of 175
TypeLabelDescription
Statement
 
Theoremne0gt0 6801 A nonzero nonnegative number is positive.
|- ((A e. RR /\ 0 <_ A) -> (A =/= 0 <-> 0 < A))
 
Theoremletric 6802 Trichotomy law. (The proof was shortened by Andrew Salmon, 19-Nov-2011.)
|- ((A e. RR /\ B e. RR) -> (A <_ B \/ B <_ A))
 
TheoremletricOLD 6803 Trichotomy law.
|- ((A e. RR /\ B e. RR) -> (A <_ B \/ B <_ A))
 
Theoremlecasei 6804 Ordering elimination by cases.
|- (ph -> A e. RR)   &   |- (ph -> B e. RR)   &   |- ((ph /\ A <_ B) -> ps)   &   |- ((ph /\ B <_ A) -> ps)   =>   |- (ph -> ps)
 
Theoremlelttric 6805 Trichotomy law.
|- ((A e. RR /\ B e. RR) -> (A <_ B \/ B < A))
 
Theoremltadd1 6806 Addition to both sides of 'less than'.
|- ((A e. RR /\ B e. RR /\ C e. RR) -> (A < B <-> (A + C) < (B + C)))
 
Theoremltadd2 6807 Addition to both sides of 'less than'.
|- ((A e. RR /\ B e. RR /\ C e. RR) -> (A < B <-> (C + A) < (C + B)))
 
Theoremleadd1 6808 Addition to both sides of 'less than or equal to'.
|- ((A e. RR /\ B e. RR /\ C e. RR) -> (A <_ B <-> (A + C) <_ (B + C)))
 
Theoremleadd2 6809 Addition to both sides of 'less than or equal to'.
|- ((A e. RR /\ B e. RR /\ C e. RR) -> (A <_ B <-> (C + A) <_ (C + B)))
 
Theoremltsubadd 6810 'Less than' relationship between subtraction and addition.
|- ((A e. RR /\ B e. RR /\ C e. RR) -> ((A - B) < C <-> A < (C + B)))
 
Theoremltsubadd2 6811 'Less than' relationship between subtraction and addition.
|- ((A e. RR /\ B e. RR /\ C e. RR) -> ((A - B) < C <-> A < (B + C)))
 
Theoremlesubadd 6812 'Less than or equal to' relationship between subtraction and addition.
|- ((A e. RR /\ B e. RR /\ C e. RR) -> ((A - B) <_ C <-> A <_ (C + B)))
 
Theoremlesubadd2 6813 'Less than or equal to' relationship between subtraction and addition.
|- ((A e. RR /\ B e. RR /\ C e. RR) -> ((A - B) <_ C <-> A <_ (B + C)))
 
Theoremltaddsub 6814 'Less than' relationship between addition and subtraction.
|- ((A e. RR /\ B e. RR /\ C e. RR) -> ((A + B) < C <-> A < (C - B)))
 
Theoremltaddsub2 6815 'Less than' relationship between addition and subtraction.
|- ((A e. RR /\ B e. RR /\ C e. RR) -> ((A + B) < C <-> B < (C - A)))
 
Theoremleaddsub 6816 'Less than or equal to' relationship between addition and subtraction.
|- ((A e. RR /\ B e. RR /\ C e. RR) -> ((A + B) <_ C <-> A <_ (C - B)))
 
Theoremleaddsub2 6817 'Less than or equal to' relationship between and addition and subtraction.
|- ((A e. RR /\ B e. RR /\ C e. RR) -> ((A + B) <_ C <-> B <_ (C - A)))
 
Theoremsuble 6818 Swap subtrahends in an inequality.
|- ((A e. RR /\ B e. RR /\ C e. RR) -> ((A - B) <_ C <-> (A - C) <_ B))
 
Theoremlesub 6819 Swap subtrahends in an inequality. (The proof was shortened by Andrew Salmon, 19-Nov-2011.)
|- ((A e. RR /\ B e. RR /\ C e. RR) -> (A <_ (B - C) <-> C <_ (B - A)))
 
TheoremlesubOLD 6820 Swap subtrahends in an inequality.
|- ((A e. RR /\ B e. RR /\ C e. RR) -> (A <_ (B - C) <-> C <_ (B - A)))
 
Theoremltsubadd2i 6821 'Less than' relationship between subtraction and addition.
|- A e. RR   &   |- B e. RR   &   |- C e. RR   =>   |- ((A - B) < C <-> A < (B + C))
 
Theoremlesubadd2i 6822 'Less than or equal to' relationship between subtraction and addition.
|- A e. RR   &   |- B e. RR   &   |- C e. RR   =>   |- ((A - B) <_ C <-> A <_ (B + C))
 
Theoremltaddsubi 6823 'Less than' relationship between subtraction and addition.
|- A e. RR   &   |- B e. RR   &   |- C e. RR   =>   |- ((A + B) < C <-> A < (C - B))
 
Theoremltmullem 6824 Multiplication of both sides of 'less than' by a positive number. Theorem I.19 of [Apostol] p. 20.
|- A e. RR   &   |- B e. RR   &   |- C e. RR   =>   |- (0 < C -> (A < B -> (A x. C) < (B x. C)))
 
Theoremltsub23 6825 'Less than' relationship between subtraction and addition.
|- ((A e. RR /\ B e. RR /\ C e. RR) -> ((A - B) < C <-> (A - C) < B))
 
Theoremltsub13 6826 'Less than' relationship between subtraction and addition.
|- ((A e. RR /\ B e. RR /\ C e. RR) -> (A < (B - C) <-> C < (B - A)))
 
Theoremlt2add 6827 Adding both sides of two 'less than' relations. Theorem I.25 of [Apostol] p. 20.
|- (((A e. RR /\ B e. RR) /\ (C e. RR /\ D e. RR)) -> ((A < C /\ B < D) -> (A + B) < (C + D)))
 
Theoremle2add 6828 Adding both sides of two 'less than or equal to' relations.
|- (((A e. RR /\ B e. RR) /\ (C e. RR /\ D e. RR)) -> ((A <_ C /\ B <_ D) -> (A + B) <_ (C + D)))
 
Theoremltleadd 6829 Adding both sides of two orderings.
|- (((A e. RR /\ B e. RR) /\ (C e. RR /\ D e. RR)) -> ((A < C /\ B <_ D) -> (A + B) < (C + D)))
 
Theoremleltadd 6830 Adding both sides of two orderings.
|- (((A e. RR /\ B e. RR) /\ (C e. RR /\ D e. RR)) -> ((A <_ C /\ B < D) -> (A + B) < (C + D)))
 
Theoremaddgt0 6831 The sum of 2 positive numbers is positive. (The proof was shortened by Andrew Salmon, 19-Nov-2011.)
|- (((A e. RR /\ B e. RR) /\ (0 < A /\ 0 < B)) -> 0 < (A + B))
 
Theoremaddgt0OLD 6832 The sum of 2 positive numbers is positive.
|- (((A e. RR /\ B e. RR) /\ (0 < A /\ 0 < B)) -> 0 < (A + B))
 
Theoremaddgegt0 6833 The sum of nonnegative and positive numbers is positive. (The proof was shortened by Andrew Salmon, 19-Nov-2011.)
|- (((A e. RR /\ B e. RR) /\ (0 <_ A /\ 0 < B)) -> 0 < (A + B))
 
Theoremaddgegt0OLD 6834 The sum of nonnegative and positive numbers is positive.
|- (((A e. RR /\ B e. RR) /\ (0 <_ A /\ 0 < B)) -> 0 < (A + B))
 
Theoremaddgtge0 6835 The sum of nonnegative and positive numbers is positive. (The proof was shortened by Andrew Salmon, 19-Nov-2011.)
|- (((A e. RR /\ B e. RR) /\ (0 < A /\ 0 <_ B)) -> 0 < (A + B))
 
Theoremaddgtge0OLD 6836 The sum of nonnegative and positive numbers is positive.
|- (((A e. RR /\ B e. RR) /\ (0 < A /\ 0 <_ B)) -> 0 < (A + B))
 
Theoremaddge0 6837 The sum of 2 nonnegative numbers is nonnegative. (The proof was shortened by Andrew Salmon, 19-Nov-2011.)
|- (((A e. RR /\ B e. RR) /\ (0 <_ A /\ 0 <_ B)) -> 0 <_ (A + B))
 
Theoremaddge0OLD 6838 The sum of 2 nonnegative numbers is nonnegative.
|- (((A e. RR /\ B e. RR) /\ (0 <_ A /\ 0 <_ B)) -> 0 <_ (A + B))
 
Theoremltaddpos 6839 Adding a positive number to another number increases it.
|- ((A e. RR /\ B e. RR) -> (0 < A <-> B < (B + A)))
 
Theoremltaddpos2 6840 Adding a positive number to another number increases it.
|- ((A e. RR /\ B e. RR) -> (0 < A <-> B < (A + B)))
 
Theoremltsubpos 6841 Subtracting a positive number from another number decreases it. (The proof was shortened by Andrew Salmon, 19-Nov-2011.)
|- ((A e. RR /\ B e. RR) -> (0 < A <-> (B - A) < B))
 
TheoremltsubposOLD 6842 Subtracting a positive number from another number decreases it.
|- ((A e. RR /\ B e. RR) -> (0 < A <-> (B - A) < B))
 
Theoremposdif 6843 Comparison of two numbers whose difference is positive.
|- ((A e. RR /\ B e. RR) -> (A < B <-> 0 < (B - A)))
 
Theoremltneg 6844 Negative of both sides of 'less than'. Theorem I.23 of [Apostol] p. 20.
|- ((A e. RR /\ B e. RR) -> (A < B <-> -uB < -uA))
 
Theoremltnegcon1 6845 Contraposition of negative in 'less than'.
|- ((A e. RR /\ B e. RR) -> (-uA < B <-> -uB < A))
 
Theoremleneg 6846 Negative of both sides of 'less than or equal to'.
|- ((A e. RR /\ B e. RR) -> (A <_ B <-> -uB <_ -uA))
 
Theoremlenegcon1 6847 Contraposition of negative in 'less than or equal to'.
|- ((A e. RR /\ B e. RR) -> (-uA <_ B <-> -uB <_ A))
 
Theoremlenegcon2 6848 Contraposition of negative in 'less than or equal to'.
|- ((A e. RR /\ B e. RR) -> (A <_ -uB <-> B <_ -uA))
 
Theoremlesub1 6849 Subtraction from both sides of 'less than or equal to'.
|- ((A e. RR /\ B e. RR /\ C e. RR) -> (A <_ B <-> (A - C) <_ (B - C)))
 
Theoremlesub2 6850 Subtraction of both sides of 'less than or equal to'.
|- ((A e. RR /\ B e. RR /\ C e. RR) -> (A <_ B <-> (C - B) <_ (C - A)))
 
Theoremltsub1 6851 Subtraction from both sides of 'less than'. (Contributed by FL, 3-Jan-2008.)
|- ((A e. RR /\ B e. RR /\ C e. RR) -> (A < B <-> (A - C) < (B - C)))
 
Theoremltsub2 6852 Subtraction of both sides of 'less than'.
|- ((A e. RR /\ B e. RR /\ C e. RR) -> (A < B <-> (C - B) < (C - A)))
 
Theoremltaddposi 6853 Adding a positive number to another number increases it.
|- A e. RR   &   |- B e. RR   =>   |- (0 < A <-> B < (B + A))
 
Theoremposdifi 6854 Comparison of two numbers whose difference is positive.
|- A e. RR   &   |- B e. RR   =>   |- (A < B <-> 0 < (B - A))
 
Theoremltnegcon1i 6855 Contraposition of negative in 'less than'.
|- A e. RR   &   |- B e. RR   =>   |- (-uA < B <-> -uB < A)
 
Theoremlenegcon1i 6856 Contraposition of negative in 'less than or equal to'.
|- A e. RR   &   |- B e. RR   =>   |- (-uA <_ B <-> -uB <_ A)
 
Theoremlt0neg1 6857 Comparison of a number and its negative to zero. Theorem I.23 of [Apostol] p. 20.
|- (A e. RR -> (A < 0 <-> 0 < -uA))
 
Theoremlt0neg2 6858 Comparison of a number and its negative to zero.
|- (A e. RR -> (0 < A <-> -uA < 0))
 
Theoremle0neg1 6859 Comparison of a number and its negative to zero.
|- (A e. RR -> (A <_ 0 <-> 0 <_ -uA))
 
Theoremle0neg2 6860 Comparison of a number and its negative to zero.
|- (A e. RR -> (0 <_ A <-> -uA <_ 0))
 
Theoremaddge01 6861 A number is less than or equal to itself plus a nonnegative number.
|- ((A e. RR /\ B e. RR) -> (0 <_ B <-> A <_ (A + B)))
 
Theoremaddge02 6862 A number is less than or equal to itself plus a nonnegative number.
|- ((A e. RR /\ B e. RR) -> (0 <_ B <-> A <_ (B + A)))
 
Theoremsubge0 6863 Nonnegative subtraction.
|- ((A e. RR /\ B e. RR) -> (0 <_ (A - B) <-> B <_ A))
 
Theoremsuble0 6864 Nonpositive subtraction.
|- ((A e. RR /\ B e. RR) -> ((A - B) <_ 0 <-> A <_ B))
 
Theoremsubge0i 6865 Nonnegative subtraction.
|- A e. RR   &   |- B e. RR   =>   |- (0 <_ (A - B) <-> B <_ A)
 
Theoremsubge02 6866 Nonnegative subtraction.
|- ((A e. RR /\ B e. RR) -> (0 <_ B <-> (A - B) <_ A))
 
Theoremlesub0 6867 Lemma to show a nonnegative number is zero.
|- ((A e. RR /\ B e. RR) -> ((0 <_ A /\ B <_ (B - A)) <-> A = 0))
 
Theoremmulge0 6868 The product of two nonnegative numbers is nonnegative.
|- (((A e. RR /\ 0 <_ A) /\ (B e. RR /\ 0 <_ B)) -> 0 <_ (A x. B))
 
Theoremmulge0OLD 6869 The product of two nonnegative numbers is nonnegative.
|- (((A e. RR /\ B e. RR) /\ (0 <_ A /\ 0 <_ B)) -> 0 <_ (A x. B))
 
Theoremmullt0 6870 The product of two negative numbers is positive. (Contributed by Jeffrey Hankins, 8-Jun-2009.)
|- (((A e. RR /\ A < 0) /\ (B e. RR /\ B < 0)) -> 0 < (A x. B))
 
Theoremlt01 6871 0 is less than 1. Theorem I.21 of [Apostol] p. 20.
|- 0 < 1
 
Reciprocals
 
Theoremixi 6872 _i times itself is minus 1. (The proof was shortened by Andrew Salmon, 19-Nov-2011.)
|- (_i x. _i) = -u1
 
TheoremixiOLD 6873 _i times itself is minus 1.
|- (_i x. _i) = -u1
 
Theoremrecextlem1 6874 Lemma for recex 6876.
 
Theoremrecextlem2 6875 Lemma for recex 6876.
 
Theoremrecex 6876 Existence of reciprocal of nonzero complex number. (Contributed by Eric Schmidt, 22-May-2007.)
|- ((A e. CC /\ A =/= 0) -> E.x e. CC (A x. x) = 1)
 
Theoremrecexi 6877 Existence of reciprocals.
|- A e. CC   &   |- A =/= 0   =>   |- E.x e. CC (A x. x) = 1
 
Theoremmulcani 6878 Cancellation law for multiplication. Theorem I.7 of [Apostol] p. 18.
|- A e. CC   &   |- B e. CC   &   |- C e. CC   &   |- C =/= 0   =>   |- ((C x. A) = (C x. B) <-> A = B)
 
Theoremmulcant2i 6879 Cancellation law for multiplication. Theorem I.7 of [Apostol] p. 18. Illustrates use of keephyp 3027.
|- C =/= 0   =>   |- ((A e. CC /\ B e. CC /\ C e. CC) -> ((C x. A) = (C x. B) <-> A = B))
 
Theoremmulcan 6880 Cancellation law for multiplication (full theorem form). Theorem I.7 of [Apostol] p. 18. Illustrates use of dedth 3011 and elimne0 6469.
|- ((A e. CC /\ B e. CC /\ (C e. CC /\ C =/= 0)) -> ((C x. A) = (C x. B) <-> A = B))
 
Theoremmulcan2 6881 Cancellation law for multiplication.
|- ((A e. CC /\ B e. CC /\ (C e. CC /\ C =/= 0)) -> ((A x. C) = (B x. C) <-> A = B))
 
Theoremmul0ori 6882 If a product is zero, one of its factors must be zero. Theorem I.11 of [Apostol] p. 18.
|- A e. CC   &   |- B e. CC   =>   |- ((A x. B) = 0 <-> (A = 0 \/ B = 0))
 
Theoremmsq0i 6883 A number is zero iff its square is zero (where square is represented using multiplication).
|- A e. CC   =>   |- ((A x. A) = 0 <-> A = 0)
 
Theoremmul0or 6884 If a product is zero, one of its factors must be zero. Theorem I.11 of [Apostol] p. 18.
|- ((A e. CC /\ B e. CC) -> ((A x. B) = 0 <-> (A = 0 \/ B = 0)))
 
Theoremmulne0b 6885 The product of two nonzero numbers is nonzero. (The proof was shortened by Andrew Salmon, 19-Nov-2011.)
|- ((A e. CC /\ B e. CC) -> ((A =/= 0 /\ B =/= 0) <-> (A x. B) =/= 0))
 
Theoremmulne0bOLD 6886 The product of two nonzero numbers is nonzero.
|- ((A e. CC /\ B e. CC) -> ((A =/= 0 /\ B =/= 0) <-> (A x. B) =/= 0))
 
Theoremmulne0 6887 The product of two nonzero numbers is nonzero.
|- (((A e. CC /\ A =/= 0) /\ (B e. CC /\ B =/= 0)) -> (A x. B) =/= 0)
 
Theoremmulne0i 6888 The product of two nonzero numbers is nonzero.
|- A e. CC   &   |- B e. CC   &   |- A =/= 0   &   |- B =/= 0   =>   |- (A x. B) =/= 0
 
Theoremmuleqadd 6889 Property of numbers whose product equals their sum. Equation 5 of [Kreyszig] p. 12.
|- ((A e. CC /\ B e. CC) -> ((A x. B) = (A + B) <-> ((A - 1) x. (B - 1)) = 1))
 
Theoremreceui 6890 Existential uniqueness of reciprocals. Theorem I.8 of [Apostol] p. 18.
|- A e. CC   &   |- B e. CC   &   |- A =/= 0   =>   |- E!x e. CC (A x. x) = B
 
Theoremmulnzcnopr 6891 Multiplication maps nonzero complex numbers to nonzero complex numbers. (Contributed by Steve Rodriguez, 23-Feb-2007.)
|- ( x. |` ((CC \ {0}) X. (CC \ {0}))):((CC \ {0}) X. (CC \ {0}))-->(CC \ {0})
 
Division
 
Definitiondf-div 6892 Define division. Theorem divmuli 6894 relates it to multiplication, and divcli 6899 and redivcli 6976 prove its closure laws.
|- / = {<.<.x, y>., z>. | ((x e. CC /\ y e. (CC \ {0})) /\ z = (iota_w e. CC(y x. w) = x))}
 
Theoremdivvali 6893 Value of division: the (unique) element x such that (B x. x) = A. This is meaningful only when B is nonzero.
|- A e. CC   &   |- B e. CC   &   |- B =/= 0   =>   |- (A / B) = (iota_x e. CC(B x. x) = A)
 
Theoremdivmuli 6894 Relationship between division and multiplication.
|- A e. CC   &   |- B e. CC   &   |- C e. CC   &   |- B =/= 0   =>   |- ((A / B) = C <-> (B x. C) = A)
 
Theoremdivmulzi 6895 Relationship between division and multiplication.
|- A e. CC   &   |- B e. CC   &   |- C e. CC   =>   |- (B =/= 0 -> ((A / B) = C <-> (B x. C) = A))
 
Theoremdivmul 6896 Relationship between division and multiplication.
|- ((A e. CC /\ B e. CC /\ (C e. CC /\ C =/= 0)) -> ((A / C) = B <-> (C x. B) = A))
 
Theoremdivmul2 6897 Relationship between division and multiplication.
|- ((A e. CC /\ B e. CC /\ (C e. CC /\ C =/= 0)) -> ((A / C) = B <-> A = (C x. B)))
 
Theoremdivmul3 6898 Relationship between division and multiplication.
|- ((A e. CC /\ B e. CC /\ (C e. CC /\ C =/= 0)) -> ((A / C) = B <-> A = (B x. C)))
 
Theoremdivcli 6899 Closure law for division.
|- A e. CC   &   |- B e. CC   &   |- B =/= 0   =>   |- (A / B) e. CC
 
Theoremdivclzi 6900 Closure law for division.
|- A e. CC   &   |- B e. CC   =>   |- (B =/= 0 -> (A / B) e. CC)

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