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| Type | Label | Description |
|---|---|---|
| Statement | ||
| Theorem | map0e 5401 | Set exponentiation with an empty exponent (ordinal number 0) is ordinal number 1. Exercise 4.42(a) of [Mendelson] p. 255. |
| Theorem | map0b 5402 | Set exponentiation with an empty base is the empty set, provided the exponent is non-empty. Theorem 96 of [Suppes] p. 89. |
| Theorem | map0 5403 | Set exponentiation is empty iff the base is empty and the exponent is not empty. Theorem 97 of [Suppes] p. 89. |
| Theorem | mapsn 5404 | The value of set exponentiation with a singleton exponent. Theorem 98 of [Suppes] p. 89. |
| Theorem | mapss 5405 | Subset inheritance for set exponentiation. Theorem 99 of [Suppes] p. 89. |
| Infinite Cartesian products | ||
| Syntax | cixp 5406 | Extend class notation to include infinite Cartesian products. |
| Definition | df-ixp 5407 |
Definition of infinite Cartesian product of [Enderton] p. 54. Enderton
uses a bold "X" with |
| Theorem | elixp2 5408 | Membership in an infinite Cartesian product. See df-ixp 5407 for discussion of the notation. |
| Theorem | elixp 5409 | Membership in an infinite Cartesian product. |
| Theorem | elixpconst 5410 |
Membership in an infinite Cartesian product of a constant |
| Theorem | ixpconst 5411 |
Infinite Cartesian product of a constant |
| Theorem | ixpeq1 5412 | Equality theorem for infinite Cartesian product. |
| Theorem | ss2ixp 5413 | Subclass theorem for infinite Cartesian product. |
| Theorem | ixpeq2 5414 | Equality theorem for infinite Cartesian product. |
| Theorem | ixpf 5415 | A member of an infinite Cartesian product maps to the indexed union of the product argument. Remark in [Enderton] p. 54. |
| Theorem | uniixp 5416 | The union of an infinite Cartesian product is included in a cross product. |
| Theorem | ixpexg 5417 |
The existence of an infinite Cartesian product. |
| Theorem | ixp0x 5418 | An infinite Cartesian product with an empty index set. |
| Theorem | 0elixp 5419 | Membership of the empty set in an infinite Cartesian product. (Contributed by Steve Rodriguez, 29-Sep-2006.) |
| Theorem | ixp0 5420 |
The infinite Cartesian product of a family |
| Theorem | mapixp 5421 |
Express set exponentiation in terms of an infinite Cartesian product.
Remark in [Stoll] p. 47. Note that
|
| Theorem | ixpssmap 5422 | An infinite Cartesian product is a subset of set exponentation. Remark in [Enderton] p. 54. |
| Equinumerosity | ||
| Syntax | cen 5423 | Extend class definition to include the equinumerosity relation ("approximately equals" symbol) |
| Syntax | cdom 5424 | Extend class definition to include the dominance relation (curly less-than-or-equal) |
| Syntax | csdm 5425 | Extend class definition to include the strict dominance relation (curly less-than) |
| Syntax | cfn 5426 | Extend class definition to include the class of all finite sets. |
| Definition | df-en 5427 |
Define the equinumerosity relation. Definition of [Enderton] p. 129.
We define |
| Definition | df-dom 5428 | Define the dominance relation. For an alternate definition see dfdom2 5443. Compare Definition of [Enderton] p. 145. Typical textbook definitions are derived as brdom 5437 and domen 5438. |
| Definition | df-sdom 5429 | Define the strict dominance relation. Alternate possible definitions are derived as brsdom 5440 and brsdom2 5524. Definition 3 of [Suppes] p. 97. |
| Definition | df-fin 5430 |
Define the (proper) class of all finite sets. Similar to Definition
10.29 of [TakeutiZaring] p. 91,
whose "Fin(a)" corresponds to
our " |
| Theorem | relen 5431 | Equinumerosity is a relation. |
| Theorem | reldom 5432 | Dominance is a relation. |
| Theorem | relsdom 5433 | Strict dominance is a relation. |
| Theorem | breng 5434 | Equinumerosity relation. |
| Theorem | brdomg 5435 | Dominance relation. |
| Theorem | bren 5436 | Equinumerosity relation. Compare Definition of [Enderton] p. 129. |
| Theorem | brdom 5437 | Dominance relation. |
| Theorem | domen 5438 | Dominance in terms of equinumerosity. Example 1 of [Enderton] p. 146. |
| Theorem | domeng 5439 | Dominance in terms of equinumerosity, with the sethood requirement expressed as an antecedent. Example 1 of [Enderton] p. 146. |
| Theorem | brsdom 5440 |
Strict dominance relation, meaning " |
| Theorem | isfi 5441 |
Express " |
| Theorem | enssdom 5442 | Equinumerosity implies dominance. |
| Theorem | dfdom2 5443 | Alternate definition of dominance. |
| Theorem | endom 5444 | Equinumerosity implies dominance. Theorem 15 of [Suppes] p. 94. |
| Theorem | sdomdom 5445 | Strict dominance implies dominance. |
| Theorem | sdomnen 5446 | Strict dominance implies non-equinumerosity. |
| Theorem | brdom2 5447 | Dominance in terms of strict dominance and equinumerosity. Theorem 22(iv) of [Suppes] p. 97. |
| Theorem | bren2 5448 | Equinumerosity expressed in terms of dominance and strict dominance. |
| Theorem | enrefg 5449 | Equinumerosity is reflexive. Theorem 1 of [Suppes] p. 92. |
| Theorem | enref 5450 | Equinumerosity is reflexive. Theorem 1 of [Suppes] p. 92. |
| Theorem | eqeng 5451 | Equality implies equinumerosity. |
| Theorem | domrefg 5452 | Dominance is reflexive. |
| Theorem | f1oen2g 5453 | The domain and range of a one-to-one, onto function are equinumerous. This variation of f1oeng 5454 does not require the Axiom of Replacement. |
| Theorem | f1oeng 5454 | The domain and range of a one-to-one, onto function are equinumerous. |
| Theorem | f1domg 5455 | The domain of a one-to-one function is dominated by its codomain. |
| Theorem | f1dom2g 5456 | The domain of a one-to-one function is dominated by its codomain. |
| Theorem | f1oen 5457 | The domain and range of a one-to-one, onto function are equinumerous. |
| Theorem | f1dom 5458 | The domain of a one-to-one function is dominated by its codomain. |
| Theorem | en2d 5459 | Equinumerosity inference from an implicit one-to-one onto function. |
| Theorem | en3d 5460 | Equinumerosity inference from an implicit one-to-one onto function. |
| Theorem | en2 5461 | Equinumerosity inference from an implicit one-to-one onto function. |
| Theorem | en3 5462 | Equinumerosity inference from an implicit one-to-one onto function. |
| Theorem | dom2d 5463 | A mapping (first hypothesis) that is one-to-one (second hypothesis) implies its domain is dominated by its codomain. |
| Theorem | dom2 5464 |
A mapping (first hypothesis) that is one-to-one (second hypothesis)
implies its domain is dominated by its codomain. |
| Theorem | idssen 5465 | Equality implies equinumerosity. |
| Theorem | dmen 5466 | The domain of equinumerosity. |
| Theorem | ssdomg 5467 | A set dominates its subsets. Theorem 16 of [Suppes] p. 94. |
| Theorem | ssdom2g 5468 | A set dominates its subsets. Theorem 16 of [Suppes] p. 94. |
| Theorem | ener 5469 | Equinumerosity is an equivalence relation. |
| Theorem | ensymg 5470 | Symmetry of equinumerosity. Theorem 2 of [Suppes] p. 92. |
| Theorem | ensym 5471 | Symmetry of equinumerosity. Theorem 2 of [Suppes] p. 92. |
| Theorem | ensymi 5472 | Symmetry of equinumerosity. Theorem 2 of [Suppes] p. 92. |
| Theorem | entr 5473 | Transitivity of equinumerosity. Theorem 3 of [Suppes] p. 92. |
| Theorem | domtr 5474 | Transitivity of dominance relation. Theorem 17 of [Suppes] p. 94. |
| Theorem | entri 5475 | A chained equinumerosity inference. |
| Theorem | entr2i 5476 | A chained equinumerosity inference. |
| Theorem | entr3i 5477 | A chained equinumerosity inference. |
| Theorem | entr4i 5478 | A chained equinumerosity inference. |
| Theorem | endomtr 5479 | Transitivity of equinumerosity and dominance. |
| Theorem | domentr 5480 | Transitivity of dominance and equinumerosity. |
| Theorem | f1imaen 5481 | A one-to-one function's image under a subset of its domain is equinumerous to the subset. |
| Theorem | en0 5482 | The empty set is equinumerous only to itself. Exercise 1 of [TakeutiZaring] p. 88. |
| Theorem | ensn1 5483 | A singleton is equinumerous to ordinal one. |
| Theorem | ensn1g 5484 | A singleton is equinumerous to ordinal one. |
| Theorem | en1 5485 | A set is equinumerous to ordinal one iff it is a singleton. |
| Theorem | 2dom 5486 | A set that dominates ordinal 2 has at least 2 different members. |
| Theorem | fundmen 5487 | A function is equinumerous to its domain. Exercise 4 of [Suppes] p. 98. |
| Theorem | mapsnen 5488 | Set exponentiation to a singleton exponent is equinumerous to its base. Exercise 4.43 of [Mendelson] p. 255. |
| Theorem | map1 5489 | Set exponentiation: ordinal 1 to any set is equinumerous to ordinal 1. Exercise 4.42(b) of [Mendelson] p. 255. |
| Theorem | en2sn 5490 | Two singletons are equinumerous. |
| Theorem | snfi 5491 | A singleton is finite. |
| Theorem | fiprc 5492 | The class of finite sets is a proper class. (Contributed by Jeffrey Hankins, 10-Oct-2008.) |
| Theorem | unen 5493 | Equinumerosity of union of disjoint sets. Theorem 4 of [Suppes] p. 92. |
| Theorem | xpsnen 5494 | A set is equinumerous to its cross-product with a singleton. Proposition 4.22(c) of [Mendelson] p. 254. |
| Theorem | xpsneng 5495 | A set is equinumerous to its cross-product with a singleton. Proposition 4.22(c) of [Mendelson] p. 254. |
| Theorem | endisj 5496 | Any two sets are equinumerous to disjoint sets. Exercise 4.39 of [Mendelson] p. 255. |
| Theorem | undom 5497 | Dominance law for union. Proposition 4.24(a) of [Mendelson] p. 257. |
| Theorem | xpcomen 5498 | Commutative law for equinumerosity of cross product. Proposition 4.22(d) of [Mendelson] p. 254. |
| Theorem | xpcomeng 5499 | Commutative law for equinumerosity of cross product. Proposition 4.22(d) of [Mendelson] p. 254. |
| Theorem | xpassen 5500 | Associative law for equinumerosity of cross product. Proposition 4.22(e) of [Mendelson] p. 254. |
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