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Theorem joinval2lem 15486
Description: Lemma for joinval2 15487 and joineu 15488. (Contributed by NM, 12-Sep-2018.) TODO: combine this through joineu into joinlem?
Hypotheses
Ref Expression
joinval2.b  |-  B  =  ( Base `  K
)
joinval2.l  |-  .<_  =  ( le `  K )
joinval2.j  |-  .\/  =  ( join `  K )
joinval2.k  |-  ( ph  ->  K  e.  V )
joinval2.x  |-  ( ph  ->  X  e.  B )
joinval2.y  |-  ( ph  ->  Y  e.  B )
Assertion
Ref Expression
joinval2lem  |-  ( ( X  e.  B  /\  Y  e.  B )  ->  ( ( A. y  e.  { X ,  Y } y  .<_  x  /\  A. z  e.  B  ( A. y  e.  { X ,  Y }
y  .<_  z  ->  x  .<_  z ) )  <->  ( ( X  .<_  x  /\  Y  .<_  x )  /\  A. z  e.  B  (
( X  .<_  z  /\  Y  .<_  z )  ->  x  .<_  z ) ) ) )
Distinct variable groups:    x, z, B    x,  .\/ , z    x, y, K, z    y,  .<_    x, X, y, z    x, Y, y, z
Allowed substitution hints:    ph( x, y, z)    B( y)    .\/ ( y)    .<_ ( x, z)    V( x, y, z)

Proof of Theorem joinval2lem
StepHypRef Expression
1 breq1 4445 . . 3  |-  ( y  =  X  ->  (
y  .<_  x  <->  X  .<_  x ) )
2 breq1 4445 . . 3  |-  ( y  =  Y  ->  (
y  .<_  x  <->  Y  .<_  x ) )
31, 2ralprg 4071 . 2  |-  ( ( X  e.  B  /\  Y  e.  B )  ->  ( A. y  e. 
{ X ,  Y } y  .<_  x  <->  ( X  .<_  x  /\  Y  .<_  x ) ) )
4 breq1 4445 . . . . 5  |-  ( y  =  X  ->  (
y  .<_  z  <->  X  .<_  z ) )
5 breq1 4445 . . . . 5  |-  ( y  =  Y  ->  (
y  .<_  z  <->  Y  .<_  z ) )
64, 5ralprg 4071 . . . 4  |-  ( ( X  e.  B  /\  Y  e.  B )  ->  ( A. y  e. 
{ X ,  Y } y  .<_  z  <->  ( X  .<_  z  /\  Y  .<_  z ) ) )
76imbi1d 317 . . 3  |-  ( ( X  e.  B  /\  Y  e.  B )  ->  ( ( A. y  e.  { X ,  Y } y  .<_  z  ->  x  .<_  z )  <->  ( ( X  .<_  z  /\  Y  .<_  z )  ->  x  .<_  z ) ) )
87ralbidv 2898 . 2  |-  ( ( X  e.  B  /\  Y  e.  B )  ->  ( A. z  e.  B  ( A. y  e.  { X ,  Y } y  .<_  z  ->  x  .<_  z )  <->  A. z  e.  B  ( ( X  .<_  z  /\  Y  .<_  z )  ->  x  .<_  z ) ) )
93, 8anbi12d 710 1  |-  ( ( X  e.  B  /\  Y  e.  B )  ->  ( ( A. y  e.  { X ,  Y } y  .<_  x  /\  A. z  e.  B  ( A. y  e.  { X ,  Y }
y  .<_  z  ->  x  .<_  z ) )  <->  ( ( X  .<_  x  /\  Y  .<_  x )  /\  A. z  e.  B  (
( X  .<_  z  /\  Y  .<_  z )  ->  x  .<_  z ) ) ) )
Colors of variables: wff setvar class
Syntax hints:    -> wi 4    <-> wb 184    /\ wa 369    = wceq 1374    e. wcel 1762   A.wral 2809   {cpr 4024   class class class wbr 4442   ` cfv 5581   Basecbs 14481   lecple 14553   joincjn 15422
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1596  ax-4 1607  ax-5 1675  ax-6 1714  ax-7 1734  ax-10 1781  ax-11 1786  ax-12 1798  ax-13 1963  ax-ext 2440
This theorem depends on definitions:  df-bi 185  df-or 370  df-an 371  df-3an 970  df-tru 1377  df-ex 1592  df-nf 1595  df-sb 1707  df-clab 2448  df-cleq 2454  df-clel 2457  df-nfc 2612  df-ral 2814  df-rab 2818  df-v 3110  df-sbc 3327  df-dif 3474  df-un 3476  df-in 3478  df-ss 3485  df-nul 3781  df-if 3935  df-sn 4023  df-pr 4025  df-op 4029  df-br 4443
This theorem is referenced by:  joinval2  15487  joineu  15488
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