Theorem hbaes 1506

Description: Rule that applies hbae 1505 to antecedent.

Hypothesis

Ref	Expression
hbalequs.1	|- (A.zA.x x = y -> ph)

Assertion

Ref	Expression
hbaes	|- (A.x x = y -> ph)

Proof of Theorem hbaes

Step	Hyp	Ref	Expression
1		hbae 1505	. 2 |- (A.x x = y -> A.zA.x x = y)
2		hbalequs.1	. 2 |- (A.zA.x x = y -> ph)
3	1, 2	syl 12	1 |- (A.x x = y -> ph)

Syntax hints:   -> wi 3  A.wal 1296   = wceq 1298

This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-7 1304  ax-gen 1305  ax-10 1308  ax-12 1310  ax-4 1319  ax-5o 1321  ax-10o 1500

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