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Theorem dissym1 30866
Description: A symmetry with  \/.

See negsym1 30862 for more information. (Contributed by Anthony Hart, 4-Sep-2011.)

Assertion
Ref Expression
dissym1  |-  ( ( ps  \/  ( ps  \/ F.  ) )  ->  ( ps  \/  ph ) )

Proof of Theorem dissym1
StepHypRef Expression
1 orc 386 . 2  |-  ( ps 
->  ( ps  \/  ph ) )
2 falim 1451 . . 3  |-  ( F. 
->  ph )
32orim2i 520 . 2  |-  ( ( ps  \/ F.  )  ->  ( ps  \/  ph ) )
41, 3jaoi 380 1  |-  ( ( ps  \/  ( ps  \/ F.  ) )  ->  ( ps  \/  ph ) )
Colors of variables: wff setvar class
Syntax hints:    -> wi 4    \/ wo 369   F. wfal 1442
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This theorem depends on definitions:  df-bi 188  df-or 371  df-tru 1440  df-fal 1443
This theorem is referenced by: (None)
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