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Theorem ceqex 2391
Description: Equality implies equivalence with substitution.
Assertion
Ref Expression
ceqex |- (x = A -> (ph <-> E.x(x = A /\ ph)))
Distinct variable group:   x,A

Proof of Theorem ceqex
StepHypRef Expression
1 19.8a 1376 . . 3 |- (x = A -> E.x x = A)
2 isset 2296 . . 3 |- (A e. _V <-> E.x x = A)
31, 2sylibr 217 . 2 |- (x = A -> A e. _V)
4 eqeq2 1893 . . . 4 |- (y = A -> (x = y <-> x = A))
54anbi1d 679 . . . . . 6 |- (y = A -> ((x = y /\ ph) <-> (x = A /\ ph)))
65exbidv 1657 . . . . 5 |- (y = A -> (E.x(x = y /\ ph) <-> E.x(x = A /\ ph)))
76bibi2d 680 . . . 4 |- (y = A -> ((ph <-> E.x(x = y /\ ph)) <-> (ph <-> E.x(x = A /\ ph))))
84, 7imbi12d 688 . . 3 |- (y = A -> ((x = y -> (ph <-> E.x(x = y /\ ph))) <-> (x = A -> (ph <-> E.x(x = A /\ ph)))))
9 19.8a 1376 . . . . 5 |- ((x = y /\ ph) -> E.x(x = y /\ ph))
109ex 402 . . . 4 |- (x = y -> (ph -> E.x(x = y /\ ph)))
11 ax-4 1319 . . . . . 6 |- (A.x(x = y -> ph) -> (x = y -> ph))
1211com12 14 . . . . 5 |- (x = y -> (A.x(x = y -> ph) -> ph))
13 visset 2295 . . . . . 6 |- y e. _V
1413alexeq 2390 . . . . 5 |- (A.x(x = y -> ph) <-> E.x(x = y /\ ph))
1512, 14syl5ibr 224 . . . 4 |- (x = y -> (E.x(x = y /\ ph) -> ph))
1610, 15impbid 574 . . 3 |- (x = y -> (ph <-> E.x(x = y /\ ph)))
178, 16vtoclg 2346 . 2 |- (A e. _V -> (x = A -> (ph <-> E.x(x = A /\ ph))))
183, 17mpcom 60 1 |- (x = A -> (ph <-> E.x(x = A /\ ph)))
Colors of variables: wff set class
Syntax hints:   -> wi 3   <-> wb 163   /\ wa 240  A.wal 1296   = wceq 1298   e. wcel 1300  E.wex 1326  _Vcvv 2292
This theorem is referenced by:  ceqsexg 2392  sbc6g 2472  copsexgOLD 3538
This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-7 1304  ax-gen 1305  ax-8 1306  ax-9 1307  ax-10 1308  ax-11 1309  ax-12 1310  ax-17 1317  ax-4 1319  ax-5o 1321  ax-6o 1324  ax-9o 1481  ax-10o 1500  ax-16 1580  ax-11o 1588  ax-ext 1865
This theorem depends on definitions:  df-bi 164  df-or 241  df-an 242  df-ex 1327  df-sb 1536  df-clab 1872  df-cleq 1877  df-clel 1880  df-v 2294
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