Intuitionistic Logic Explorer |
< Previous
Next >
Nearby theorems |
||
Mirrors > Home > ILE Home > Th. List > sbexyz | GIF version |
Description: Move existential quantifier in and out of substitution. Identical to sbex 1880 except that it has an additional distinct variable constraint on 𝑦 and 𝑧. (Contributed by Jim Kingdon, 29-Dec-2017.) |
Ref | Expression |
---|---|
sbexyz | ⊢ ([𝑧 / 𝑦]∃𝑥𝜑 ↔ ∃𝑥[𝑧 / 𝑦]𝜑) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | sb5 1767 | . . 3 ⊢ ([𝑧 / 𝑦]∃𝑥𝜑 ↔ ∃𝑦(𝑦 = 𝑧 ∧ ∃𝑥𝜑)) | |
2 | exdistr 1787 | . . 3 ⊢ (∃𝑦∃𝑥(𝑦 = 𝑧 ∧ 𝜑) ↔ ∃𝑦(𝑦 = 𝑧 ∧ ∃𝑥𝜑)) | |
3 | excom 1554 | . . 3 ⊢ (∃𝑦∃𝑥(𝑦 = 𝑧 ∧ 𝜑) ↔ ∃𝑥∃𝑦(𝑦 = 𝑧 ∧ 𝜑)) | |
4 | 1, 2, 3 | 3bitr2i 197 | . 2 ⊢ ([𝑧 / 𝑦]∃𝑥𝜑 ↔ ∃𝑥∃𝑦(𝑦 = 𝑧 ∧ 𝜑)) |
5 | sb5 1767 | . . 3 ⊢ ([𝑧 / 𝑦]𝜑 ↔ ∃𝑦(𝑦 = 𝑧 ∧ 𝜑)) | |
6 | 5 | exbii 1496 | . 2 ⊢ (∃𝑥[𝑧 / 𝑦]𝜑 ↔ ∃𝑥∃𝑦(𝑦 = 𝑧 ∧ 𝜑)) |
7 | 4, 6 | bitr4i 176 | 1 ⊢ ([𝑧 / 𝑦]∃𝑥𝜑 ↔ ∃𝑥[𝑧 / 𝑦]𝜑) |
Colors of variables: wff set class |
Syntax hints: ∧ wa 97 ↔ wb 98 ∃wex 1381 [wsb 1645 |
This theorem was proved from axioms: ax-1 5 ax-2 6 ax-mp 7 ax-ia1 99 ax-ia2 100 ax-ia3 101 ax-5 1336 ax-7 1337 ax-gen 1338 ax-ie1 1382 ax-ie2 1383 ax-8 1395 ax-11 1397 ax-4 1400 ax-17 1419 ax-i9 1423 ax-ial 1427 |
This theorem depends on definitions: df-bi 110 df-sb 1646 |
This theorem is referenced by: sbex 1880 |
Copyright terms: Public domain | W3C validator |