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Theorem rabeq0 3247
Description: Condition for a restricted class abstraction to be empty. (Contributed by Jeff Madsen, 7-Jun-2010.)
Assertion
Ref Expression
rabeq0 ({𝑥𝐴𝜑} = ∅ ↔ ∀𝑥𝐴 ¬ 𝜑)

Proof of Theorem rabeq0
Dummy variable 𝑦 is distinct from all other variables.
StepHypRef Expression
1 imnan 624 . . 3 ((𝑥𝐴 → ¬ 𝜑) ↔ ¬ (𝑥𝐴𝜑))
21albii 1359 . 2 (∀𝑥(𝑥𝐴 → ¬ 𝜑) ↔ ∀𝑥 ¬ (𝑥𝐴𝜑))
3 df-ral 2311 . 2 (∀𝑥𝐴 ¬ 𝜑 ↔ ∀𝑥(𝑥𝐴 → ¬ 𝜑))
4 sbn 1826 . . . 4 ([𝑦 / 𝑥] ¬ (𝑥𝐴𝜑) ↔ ¬ [𝑦 / 𝑥](𝑥𝐴𝜑))
54albii 1359 . . 3 (∀𝑦[𝑦 / 𝑥] ¬ (𝑥𝐴𝜑) ↔ ∀𝑦 ¬ [𝑦 / 𝑥](𝑥𝐴𝜑))
6 nfv 1421 . . . 4 𝑦 ¬ (𝑥𝐴𝜑)
76sb8 1736 . . 3 (∀𝑥 ¬ (𝑥𝐴𝜑) ↔ ∀𝑦[𝑦 / 𝑥] ¬ (𝑥𝐴𝜑))
8 eq0 3239 . . . 4 ({𝑥𝐴𝜑} = ∅ ↔ ∀𝑦 ¬ 𝑦 ∈ {𝑥𝐴𝜑})
9 df-rab 2315 . . . . . . . 8 {𝑥𝐴𝜑} = {𝑥 ∣ (𝑥𝐴𝜑)}
109eleq2i 2104 . . . . . . 7 (𝑦 ∈ {𝑥𝐴𝜑} ↔ 𝑦 ∈ {𝑥 ∣ (𝑥𝐴𝜑)})
11 df-clab 2027 . . . . . . 7 (𝑦 ∈ {𝑥 ∣ (𝑥𝐴𝜑)} ↔ [𝑦 / 𝑥](𝑥𝐴𝜑))
1210, 11bitri 173 . . . . . 6 (𝑦 ∈ {𝑥𝐴𝜑} ↔ [𝑦 / 𝑥](𝑥𝐴𝜑))
1312notbii 594 . . . . 5 𝑦 ∈ {𝑥𝐴𝜑} ↔ ¬ [𝑦 / 𝑥](𝑥𝐴𝜑))
1413albii 1359 . . . 4 (∀𝑦 ¬ 𝑦 ∈ {𝑥𝐴𝜑} ↔ ∀𝑦 ¬ [𝑦 / 𝑥](𝑥𝐴𝜑))
158, 14bitri 173 . . 3 ({𝑥𝐴𝜑} = ∅ ↔ ∀𝑦 ¬ [𝑦 / 𝑥](𝑥𝐴𝜑))
165, 7, 153bitr4ri 202 . 2 ({𝑥𝐴𝜑} = ∅ ↔ ∀𝑥 ¬ (𝑥𝐴𝜑))
172, 3, 163bitr4ri 202 1 ({𝑥𝐴𝜑} = ∅ ↔ ∀𝑥𝐴 ¬ 𝜑)
Colors of variables: wff set class
Syntax hints:  ¬ wn 3  wi 4  wa 97  wb 98  wal 1241   = wceq 1243  wcel 1393  [wsb 1645  {cab 2026  wral 2306  {crab 2310  c0 3224
This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 99  ax-ia2 100  ax-ia3 101  ax-in1 544  ax-in2 545  ax-io 630  ax-5 1336  ax-7 1337  ax-gen 1338  ax-ie1 1382  ax-ie2 1383  ax-8 1395  ax-10 1396  ax-11 1397  ax-i12 1398  ax-bndl 1399  ax-4 1400  ax-17 1419  ax-i9 1423  ax-ial 1427  ax-i5r 1428  ax-ext 2022
This theorem depends on definitions:  df-bi 110  df-tru 1246  df-fal 1249  df-nf 1350  df-sb 1646  df-clab 2027  df-cleq 2033  df-clel 2036  df-nfc 2167  df-ral 2311  df-rab 2315  df-v 2559  df-dif 2920  df-nul 3225
This theorem is referenced by:  rabnc  3250  rabrsndc  3438  ssfiexmid  6336  diffitest  6344  iooidg  8778  icc0r  8795  fznlem  8905
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