Theorem orbi1i 680

Description: Inference adding a right disjunct to both sides of a logical equivalence. (Contributed by NM, 5-Aug-1993.)

Hypothesis

Ref	Expression
orbi2i.1	⊢ (𝜑 ↔ 𝜓)

Assertion

Ref	Expression
orbi1i	⊢ ((𝜑 ∨ 𝜒) ↔ (𝜓 ∨ 𝜒))

Proof of Theorem orbi1i

Step	Hyp	Ref	Expression
1		orcom 647	. 2 ⊢ ((𝜑 ∨ 𝜒) ↔ (𝜒 ∨ 𝜑))
2		orbi2i.1	. . 3 ⊢ (𝜑 ↔ 𝜓)
3	2	orbi2i 679	. 2 ⊢ ((𝜒 ∨ 𝜑) ↔ (𝜒 ∨ 𝜓))
4		orcom 647	. 2 ⊢ ((𝜒 ∨ 𝜓) ↔ (𝜓 ∨ 𝜒))
5	1, 3, 4	3bitri 195	1 ⊢ ((𝜑 ∨ 𝜒) ↔ (𝜓 ∨ 𝜒))

Syntax hints:   ↔ wb 98   ∨ wo 629

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 99  ax-ia2 100  ax-ia3 101  ax-io 630

This theorem depends on definitions:  df-bi 110

This theorem is referenced by:  orbi12i  681  orordi  690  dcan  842  3or6  1218  19.45  1573  sbequilem  1719  unass  3100  frecsuc  5991  elznn0nn  8259