Theorem ax11i 1602

Description: Inference that has ax-11 1397 (without A. y) as its conclusion and doesn't require ax-10 1396, ax-11 1397, or ax-12 1402 for its proof. The hypotheses may be eliminable without one or more of these axioms in special cases. Proof similar to Lemma 16 of [Tarski] p. 70. (Contributed by NM, 20-May-2008.)

Hypotheses

Ref	Expression
ax11i.1	|- ( x = y -> ( ph <-> ps ) )
ax11i.2	|- ( ps -> A. x ps )

Assertion

Ref	Expression
ax11i	|- ( x = y -> ( ph -> A. x ( x = y -> ph ) ) )

Proof of Theorem ax11i

Step	Hyp	Ref	Expression
1		ax11i.1	. 2 |- ( x = y -> ( ph <-> ps ) )
2		ax11i.2	. . 3 |- ( ps -> A. x ps )
3	1	biimprcd 149	. . 3 |- ( ps -> ( x = y -> ph ) )
4	2, 3	alrimih 1358	. 2 |- ( ps -> A. x ( x = y -> ph ) )
5	1, 4	syl6bi 152	1 |- ( x = y -> ( ph -> A. x ( x = y -> ph ) ) )

Syntax hints:   -> wi 4   <-> wb 98   A.wal 1241

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 99  ax-ia2 100  ax-ia3 101  ax-5 1336  ax-gen 1338

This theorem depends on definitions:  df-bi 110

This theorem is referenced by: (None)