Theorem 3impexpbicomi 1328

Description: Deduction form of 3impexpbicom 1327. (Contributed by Alan Sare, 31-Dec-2011.)

Hypothesis

Ref	Expression
3impexpbicomi.1	|- ( ( ph /\ ps /\ ch ) -> ( th <-> ta ) )

Assertion

Ref	Expression
3impexpbicomi	|- ( ph -> ( ps -> ( ch -> ( ta <-> th ) ) ) )

Proof of Theorem 3impexpbicomi

Step	Hyp	Ref	Expression
1		3impexpbicomi.1	. . 3 |- ( ( ph /\ ps /\ ch ) -> ( th <-> ta ) )
2	1	bicomd 129	. 2 |- ( ( ph /\ ps /\ ch ) -> ( ta <-> th ) )
3	2	3exp 1103	1 |- ( ph -> ( ps -> ( ch -> ( ta <-> th ) ) ) )

Syntax hints:   -> wi 4   <-> wb 98   /\ w3a 885

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 99  ax-ia2 100  ax-ia3 101

This theorem depends on definitions:  df-bi 110  df-3an 887

This theorem is referenced by: (None)