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Theorem clf 105
Description: Evaluate a lambda expression.
Hypotheses
Ref Expression
clf.1 |- A:be
clf.2 |- C:al
clf.3 |- [x:al = C] |= [A = B]
clf.4 |- T. |= [(\x:al By:al) = B]
clf.5 |- T. |= [(\x:al Cy:al) = C]
Assertion
Ref Expression
clf |- T. |= [(\x:al AC) = B]
Distinct variable groups:   y,A   y,B   y,C   x,y,al

Proof of Theorem clf
StepHypRef Expression
1 clf.2 . 2 |- C:al
2 clf.1 . . . . 5 |- A:be
32wl 59 . . . 4 |- \x:al A:(al -> be)
43, 1wc 45 . . 3 |- (\x:al AC):be
5 clf.3 . . . 4 |- [x:al = C] |= [A = B]
62, 5eqtypi 69 . . 3 |- B:be
74, 6weqi 68 . 2 |- [(\x:al AC) = B]:*
8 clf.4 . . . 4 |- T. |= [(\x:al By:al) = B]
98ax-cb1 29 . . 3 |- T.:*
102beta 82 . . 3 |- T. |= [(\x:al Ax:al) = A]
119, 10a1i 28 . 2 |- T. |= [(\x:al Ax:al) = A]
12 weq 38 . . 3 |- = :(be -> (be -> *))
13 wv 58 . . 3 |- y:al:al
1412, 13, 9a17i 96 . . 3 |- T. |= [(\x:al = y:al) = = ]
152, 13, 9hbl1 94 . . . 4 |- T. |= [(\x:al \x:al Ay:al) = \x:al A]
16 clf.5 . . . 4 |- T. |= [(\x:al Cy:al) = C]
173, 1, 13, 15, 16hbc 100 . . 3 |- T. |= [(\x:al (\x:al AC)y:al) = (\x:al AC)]
1812, 4, 13, 6, 14, 17, 8hbov 101 . 2 |- T. |= [(\x:al [(\x:al AC) = B]y:al) = [(\x:al AC) = B]]
19 wv 58 . . . 4 |- x:al:al
203, 19wc 45 . . 3 |- (\x:al Ax:al):be
2119, 1weqi 68 . . . . 5 |- [x:al = C]:*
2221id 25 . . . 4 |- [x:al = C] |= [x:al = C]
233, 19, 22ceq2 80 . . 3 |- [x:al = C] |= [(\x:al Ax:al) = (\x:al AC)]
2412, 20, 2, 23, 5oveq12 90 . 2 |- [x:al = C] |= [[(\x:al Ax:al) = A] = [(\x:al AC) = B]]
251, 7, 11, 18, 24insti 104 1 |- T. |= [(\x:al AC) = B]
Colors of variables: type var term
Syntax hints:  tv 1   -> ht 2  *hb 3  kc 5  \kl 6   = ke 7  T.kt 8  [kbr 9   |= wffMMJ2 11  wffMMJ2t 12
This theorem was proved from axioms:  ax-syl 15  ax-jca 17  ax-simpl 20  ax-simpr 21  ax-id 24  ax-trud 26  ax-cb1 29  ax-cb2 30  ax-refl 39  ax-eqmp 42  ax-ceq 46  ax-beta 60  ax-distrc 61  ax-leq 62  ax-hbl1 93  ax-17 95  ax-inst 103
This theorem depends on definitions:  df-ov 65
This theorem is referenced by:  cl  106  cbvf  167  exmid  186  axrep  207
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